Answer:
Step-by-step explanation:
In this problem, we are substituting for x.
Let us take a look at our given answers.
x = -13 and x = -3 would not work because the numbers would not add up to -5. Since we have the positive brackets (or whatever you call them.) surrounding the x variable, that means that all numbers that are plugged into x will be positive.
-13 will be turned into 13,
13 - 8 
-5
So that is wrong.
x = 3 and x = 3 would work because plugging it in, all outcomes from the two numbers would be negative.
3 - 8 = -5
- 8 = -5
True.
The third one won't work because of the same reasons as the first one.
Then, the last one would not work well because, there is a solution.
Answer:
see attached
Step-by-step explanation:
Here's your worksheet with the blanks filled.
__
Of course, you know these log relations:
log(a^b) = b·log(a) . . . . . power property
log(a/b) = log(a) -log(b) . . . . . quotient property
log(x) = log(y) ⇔ x = y . . . . . . . . . equality property
Answer:
7³
Step-by-step explanation:
Using PEMDAS, we see that E (which stands for exponents) comes before M (which stands for multiplication) and A (which stands for addition) so the first operation you should do is 7³.
Just to remove ambiguities, the bar over the expression means it's repeating itself to infinity.
notice, the idea being, you multiply it by 10 at some power, so that you move the "recurring decimal" to the other side of the point, and then split it with a digit and "x".
now, you can plug that in your calculator, to check what you get.
