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lord [1]
3 years ago
10

Can someone please answer please ​

Mathematics
1 answer:
yan [13]3 years ago
4 0

Answer:

3(x)+2

Step-by-step explanation:

2(5)+6 = 16

3(5)+2 = 17

4(5)-5 = 15

5(5)-10 = 15

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Hey guys!! U think u can help me on this plsss... :)))
liraira [26]

Answer:

4\7

Step-by-step explanation:

8 0
3 years ago
12.5% of $100 is<br> what number?
Westkost [7]

Answer:100$-100%               100*12.5=1250

                                                    1250/100=12.5

                 ?-12.5%

Step-by-step explanation:

7 0
3 years ago
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What is a numerical expression? Give an example.
seropon [69]

Answer:

Step-by-step explanation:

The term numerical expression is made up of two words, numerical meaning numbers, and expression meaning phrase. ... A numerical expression in mathematics can be a combination of numbers, integers combined using mathematical operators such as addition, subtraction, multiplication, or division.

6 0
3 years ago
(06.02 mc) the equation of line cd is y=3x-3. Write an equation of a line perpendicular to line cd in slope intercept form that
Fynjy0 [20]

Answer:

y = - \frac{1}{3} x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 3 ← is in slope- intercept form

with slope m = 3

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{3}, hence

y = - \frac{1}{3} x + c ← is the partial equation of the perpendicular line

To find c substitute (3, 1) into the partial equation

1 = - 1 + c ⇒ c = 1 + 1 = 2

y = - \frac{1}{3} x + 2 ← equation of perpendicular line

6 0
3 years ago
Read 2 more answers
How do I do this qn?
denis-greek [22]
You can take the log of the left and right hand side, and then apply the <span>logarithm rules:

log(a</span>ˣ) = x·log(a)
log(ab) = log(a) + log(b)

log(9^(x-1) * 2^(2x+2)) = log(6^(3x))
log(9^(x-1)) + log(2^(2x+2)) = 3x log(6)
(x-1) log(9) + (2x+2) log(2) - 3x log(6) = 0
x(log9 + 2log2 - 3log6) = log9 - 2log2
x = (log9 - 2log2) / (log9 + 2log2 - 3log6)

simplifying by writing log9 = 2log3 and log6 = log2+log3

x= 2(log3 - log2) / (2log3 + 2log2 - 3log2 - 3log3) = 
x= -2(log3 - log2) / (log3 + log2) = -2 log(3/2) / log(6)

So 6^x = 4/9
3 0
3 years ago
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