F(3) = 5 [5-3=2 diff]
f(4) = 8 [8-4=4 diff] (or 2 times larger than f(3)’s diff)
If that holds true, then continue the pattern:
f(5) = 13 [2 times f(4) diff = 8 so 5 + 8 = 13]
f(6) = 22
f(7) = 39
f(8) = 72
The only problem with my answer is that it could be times 2 or ^2. My answer above assumes times 2.
Answer:
x = 5
Step-by-step explanation:
3x + 6 = 21
3x = 21 - 6
3x/3 = 15/3
x = 5
Answer:
C. 40
Step-by-step explanation:
the fraction 20/6 in a calculator makes 3.333 repeating and 40/12 does the same.
Answer:
every pair is being multi by the next number
Step-by-step explanation:
2 x 3 =6
3 x 4 = 12 so the second number goes up one every time