Recall your d = rt, distance = rate * time
now, if say, by the time they meet, Mr Cunningham has travelled "d" miles, that means Mrs Cunningham must also had travelled "d" miles as well.
However, he left 3 hours earlier, so by the time he travelled "d" miles, and took say "t" hours, for her it took 3 hour less, because she started driving 3 hours later, so, she's been on the road 3 hours less than Mr Cunningham, so by the time they meet, Mrs Cunningham has travelled then "t - 3" hours.
Where the pictures of the graph
Answer:
Option 3 is the correct answer.
Step-by-step explanation:
In this graph the red area is above the line y = -1 which represents y ≥ (-1)
Another graph is of a line y = mx + c which passes through (2, -1) and (0, 0)
where m = (y-y')/(x-x') = (1+0)/(0-2) = -1/2
and y intercept c = 0
Therefore line is y = -1/2x
and the blue area will be y ≤ -1/2x below the line.
Hence Option 3 is the answer.
Hint: if you were to graph this, and it curves, then its a linear, if not its straight, then its non linear
Answer:
Number of monthly calls = 475
Step-by-step explanation:
Given:
Plan 1 = $30 per month unlimited calls
Plan 2 = $11 + $0.04(per call)
Find:
Number of monthly calls, plan 1 better than plan 2
Computation:
Plan 1 (Cost) < Plan 2 (Cost)
30 < 11 + 0.04(x)
19 < 0.04(x)
475 < (x)
Number of monthly calls = 475