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mario62 [17]
3 years ago
6

The following table shows the number of classes that each teacher in the math department at Wilburton High School teaches. Find

the median number of classes.

Mathematics
1 answer:
LenaWriter [7]3 years ago
6 0

Answer:

4 classes

Step-by-step explanation:

4+3+5+9+3+4=28

28/6=4.6

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Please help. This is finding the area of a rectangle.
Nezavi [6.7K]

Answer:

2500 ft²

Step-by-step explanation:

The missing area at lower right in the diagram has dimensions...

(4-2 1/4) by (3 - 1 3/4) by (1 1/4)

Then area of that "Missing" space is (1.75)(1.25)= 2.1875 . . . . square inches. The area of the enclosing rectangle is ... (4 in) (3 in) = 12 square inches the area in the diagram representing the store is... 12 in² -2.1875 in² = 9.8125 in²

_

Each square inch on that diagram represents an actual area of (1 in)×(1 in) → (16 ft)×(16 ft) = 265 ft²

Then the actual store area is....

9.8125(256 ft²) = 2512 ft²

Rounded to the nearest 50 ft², this is 2500 ft².

4 0
3 years ago
Read 2 more answers
A gardening club has 36 members,of which 29 are males and the rest are females.What is the ratio of females to males?
Jlenok [28]
7:29
i found the answer by doing 29 minus 36 and the answer is how many females are on the gardening club
6 0
3 years ago
Find the quotient and remainder when the first polynomial is divided by the second 3x⁴+16x³+6x²-2x-13; x+5
ElenaW [278]

Answer:

Quotient : 3x³ + x² + x + 3

Step-by-step explanation:

Give the polynomial :

Dividend : 3x⁴+16x³+6x²-2x-13;

Divisor : x+5

Kindly check attached picture for detailed explanation.

3 0
3 years ago
What is 8.5% mutiplyed by 70
dsp73
70 x 8.5% = 70 x 0.085 = 5.95
6 0
4 years ago
Read 2 more answers
The perimeter of this triangle is 25 units. An angle bisector divides one side of the triangle into lengths of 2 and 3. Find the
grin007 [14]

Answer:

   8 and 12

Step-by-step explanation:

Sides on one side of the angle bisector are proportional to those on the other side. In the attached figure, that means

  AC/AB = CD/BD = 2/3

The perimeter is the sum of the side lengths, so is ...

  25 = AB + BC + AC

  25 = AB + 5 + (2/3)AB . . . . . . substituting AC = 2/3·AB. BC = 2+3 = 5.

  20 = 5/3·AB

  12 = AB

  AC = 2/3·12 = 8

_____

<em>Alternate solution</em>

The sum of ratio units is 2+3 = 5, so each one must stand for 25/5 = 5 units of length.

That is, the total of lengths on one side of the angle bisector (AC+CD) is 2·5 = 10 units, and the total of lengths on the other side (AB+BD) is 3·5 = 15 units. Since 2 of the 10 units are in the segment being divided (CD), the other 8 must be in that side of the triangle (AC).

Likewise, 3 of the 15 units are in the segment being divided (BD), so the other 12 units are in that side of the triangle (AB).

The remaining sides of the triangle are AB=12 and AC=8.

7 0
4 years ago
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