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2 years ago

6

The following table shows the number of classes that each teacher in the math department at Wilburton High School teaches. Find

the median number of classes.

1 answer:

LenaWriter [7]2 years ago

6 0

Answer:

4 classes

Step-by-step explanation:

4+3+5+9+3+4=28

28/6=4.6

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For her 1st birthday, Ruth's grandparents invested $1000 in an 18-year certificate for her that pays 10% compounded annually. Ho

Lyrx [107]

Answer:

The certificate will be worth $5,559.92 on Ruth's 19th birthday.

Step-by-step explanation:

The compound interest formula is given by:

$A = P(1 + \frac{r}{n})^{nt}$

Where A is the amount of money, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit t and t is the time the money is invested or borrowed for.

In this problem, we have that:

$P = 1000, n = 1, r = 0.1, t = 18$

So

$A = 1000(1 + \frac{0.1}{1})^{1*18}$

$A = 5559.92$

The certificate will be worth $5,559.92 on Ruth's 19th birthday.

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3 years ago

How many solutions does this linear system have y= 1/2x+4 <br> x+2y=-8

lara [203]

Answer:

1 solution

Step-by-step explanation:

y = 1/2x + 4

x + 2y = -8

Solve the second equation for y.

2y = -x - 8

y = -1/2x - 4

The two equations in slope-intercept form are:

y = 1/2x + 4

y = -1/2x - 4

The system consists of two lines with different slopes, so they intercept at a single point which is the solution.

Answer: 1 solution

4 0

2 years ago

The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.

valina [46]

Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.85}{2} = 0.075$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.075 = 0.925$ , so Z = 1.44.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that $\sigma = \sqrt{1.69} = 1.3$

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

A sample of n is needed, and n is found for M = 0.14. So

$M = z\frac{\sigma}{\sqrt{n}}$

$0.14 = 1.44\frac{1.3}{\sqrt{n}}$

$0.14\sqrt{n} = 1.44*1.3$

$\sqrt{n} = \frac{1.44*1.3}{0.14}$

$(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2$

$n = 178.8$

Rounding up

A sample of 179 is needed.

7 0

2 years ago

PLEASE ANSWER FAST !!

emmainna [20.7K]

Answer:

Obviously condensation

Step-by-step explanation: because it is

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2 years ago

Which statement correctly compares the two functions? GIVING BRAINLIEST!!

geniusboy [140]

Answer:

A

Step-by-step explanation:

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2 years ago

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