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3 years ago

Help me please .solve this following equation :)

Mathematics

1 answer:

mel-nik [20]3 years ago

3 0

Answer:

Step-by-step explanation:

i solve (a)

put x=2

3(2)³-4(2)²-5(2)+2=3(8)-16-10+2=24-26+2=0

so x=2 is one solution.

divide by 2 synthetically

2 |3 -4 -5 2

| 6 4 -2

|-------------------

3 2 -1 |0

3x²+2x-1=0

3x²+3x-x-1=0

3x(x+1)-1(x+1)=0

(x+1)(3x-1)=0

x=-1,1/3

so solutions are -1,1/3,2

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I’m a little confused with this? Can someone walk me through this?

mina [271]

Answer:

A. 5.8

Step-by-step explanation:

From the given graph d has two coordinates;

the first coordinates of d = (0, 0)

the second coordinate of d = (-3 , -5), that is x = -3 when traced up and y = -5 when traced horizontal

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Option A is correct

6 0

4 years ago

Answer fast!! With explanation pls

Zepler [3.9K]

D is equivalent because brackets don’t change anything here

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3 years ago

Read 2 more answers

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spin [16.1K]

Answer:

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Step-by-step explanation:

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7 0

2 years ago

4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25

jarptica [38.1K]

Answer with explanation:

$\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}$

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$