Answer:

Step-by-step explanation:
The shortest distance d, of a point (a, b, c) from a plane mx + ny + tz = r is given by:
--------------------(i)
From the question,
the point is (5, 0, -6)
the plane is x + y + z = 6
Therefore,
a = 5
b = 0
c = -6
m = 1
n = 1
t = 1
r = 6
Substitute these values into equation (i) as follows;




Therefore, the shortest distance from the point to the plane is 
Consider the function

, which has derivative

.
The linear approximation of

for some value

within a neighborhood of

is given by

Let

. Then

can be estimated to be

![\sqrt[3]{63.97}\approx4-\dfrac{0.03}{48}=3.999375](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B63.97%7D%5Capprox4-%5Cdfrac%7B0.03%7D%7B48%7D%3D3.999375)
Since

for

, it follows that

must be strictly increasing over that part of its domain, which means the linear approximation lies strictly above the function

. This means the estimated value is an overestimation.
Indeed, the actual value is closer to the number 3.999374902...
y=23x+143 hope this helps
Answer:

Hopefully, this is your desired setup. (I noticed the formula you have to fill in there.)
Have a good day.
Step-by-step explanation:
Hi.
You could use the percent change formula.
Since we know it is a percent increase then we will do new-old instead of old-new:

x is the new amount of shampoo.
16.5 is the original amount (old) of shampoo.
The percent increase is 30%=0.30 .
So we have the following equation:

We could have found the equation like this:

Subtract 16.5 on both sides:

Divide both sides by 16.5:

By us of symmetric property of equality:

x=4,3,2 or,1 are the possible