Answer:
The value of c = -0.5∈ (-1,0)
Step-by-step explanation:
<u>Step(i)</u>:-
Given function f(x) = 4x² +4x -3 on the interval [-1 ,0]
<u> Mean Value theorem</u>
Let 'f' be continuous on [a ,b] and differentiable on (a ,b). The there exists a Point 'c' in (a ,b) such that

<u>Step(ii):</u>-
Given f(x) = 4x² +4x -3 …(i)
Differentiating equation (i) with respective to 'x'
f¹(x) = 4(2x) +4(1) = 8x+4
<u>Step(iii)</u>:-
By using mean value theorem


8c+4 = -3-(-3)
8c+4 = 0
8c = -4

c ∈ (-1,0)
<u>Conclusion</u>:-
The value of c = -0.5∈ (-1,0)
<u></u>
Answer:
if you can use the app photomath or m.a.t.h. w.a.y
Step-by-step explanation:
Its A or C because Angle AEC has to be bigger then 90 degrees
<span>3(9x-9)=16+3(-2x+9)
27x - 27 = 16 - 6x + 27
27x + 6x = 16 + 27 + 27
33x = 70
x = 70/33
x = 2 4/33
In short, Your Answer would be 70/33 or 2 4/33
Hope this helps!</span>