What fraction has a value of more than 1?

What is the least common multiple of 26 and 39?

GuDViN [60]

Answer:

78

Step-by-step explanation:

Find the prime factorizations of the two numbers:

26 = 2 * 13

39 = 3 * 13

The LCM is the product of common and not common factors with the higher exponent.

LCM = 2 * 3 * 13 = 78

Answer: 78

5 0

3 years ago

Find at least 4 equivalent fraction of 14 / 16

r-ruslan [8.4K]

Answer:

hope i helped:) :)

Step-by-step explanation:

7/8

28/32

42/48

56/64

5 0

2 years ago

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A 5-mile walking trail has markers every ¼ of a mile. How many markers are there along the trail?

likoan [24]

Answer:

20 trail markers

Step-by-step explanation: I would appreciate a brainiiest

6 0

3 years ago

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Rob is making a tent out of canvas in the shape of a square pyramid. Each side of the square base is 6 feet long, and the height

Elena L [17]

The amount of balloons in the tent is 125.075 feet cube. From the given options, approximately, option D is correct

Solution:

Given, Rob is making a tent out of canvas in the shape of a square pyramid. Each side of the square base is 6 feet long, and the height is 6.3 feet.

Rob filled the tent with balloons,

We have to find which measurement BEST describes the amount of balloons in the tent?

As tent if filled with balloons the amount of balloons equals with volume of tent.

Volume of tent is given as:

$\text { volume of tent }=a^{2}+2 a \sqrt{\frac{a^{2}}{4}+h^{2}}$

where "a" is side length and "h" is height.

$\begin{array}{l}{\text { Then, Volume }=6.3^{2}+2(6.3) \sqrt{\frac{6.3^{2}}{4}+6^{2}}} \\\\ {=39.69+12.6 \sqrt{9.925+36}} \\\\ {=39.69+12.6 \times 6.7766=39.69+85.385} \\\\ {=125.075 \mathrm{ft}^{3}}\end{array}$

Hence, from the given options, approximately, option D is correct.

6 0

3 years ago

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Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

3 years ago