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The distribution of the amount of money in savings accounts for Florida State students has an average of 1,200 dollars and a sta

Anestetic [448]

Answer:

By the Central Limit Theorem, the sampling distribution of the sample mean amount of money in a savings account is approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Average of 1,200 dollars and a standard deviation of 900 dollars.

This means that $\mu = 1200, \sigma = 900$

Sample of 10.

This means that $n = 10, s = \frac{900}{\sqrt{10}} = 284.6$

The sampling distribution of the sample mean amount of money in a savings account is

By the Central Limit Theorem, approximately normal with mean of 1,200 dollars and standard deviation of 284.6 dollars.

7 0

3 years ago

Suppose you are driving 60 miles per hour. what is your rate of speed in miles per minute?

Verdich [7]

So if it is 60 miles per hour it is basically 60 miles per 60 minutes. $\frac{60}{60}$ when you simplify it, it is going to be 1/1=1 The answer is 1 mile per minute

6 0

3 years ago

Read 2 more answers

Devide 60 in the ratio of 2:3

nevsk [136]

Answer:

Let the amounts be 2x and 3x.

Then 2x+3x=60

So, 5x=60

So, x=60/5=12

So, amounts are

2x=2*12=24

And 3x=3*12=36

Hope this helps you!

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

A group of friends are playing a trivia game. players spin a spinner 2 times to find the 2 categories of trivia questions they w

Delicious77 [7]

The probability that a player will be asked a math question and then a music question is 0.03125

<h3>How to determine the probability?</h3>

The size of the sections are given as:

Music = 0.5

Sport = 0.5

Others = 1

So, the total size is:

Total = 0.5 + 0.5 + 1 + 1 + 1

Evaluate

Total = 4

The probability of asking a math question is:

P(Math) = 1/4 = 0.25

The probability of asking a music question is:

P(Music) = 0.5/4 = 0.125

The required probability is:

P(Math and Music) = P(Math) * P(Music)

This gives

P(Math and Music) = 0.25 * 0.125

Evaluate

P(Math and Music) = 0.03125

Hence, the probability that a player will be asked a math question and then a music question is 0.03125