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4 years ago

Express in Slope-Intercept Form

Mathematics

2 answers:

sweet-ann [11.9K]4 years ago

7 0

Answer:

y = (3/4)x + 2

Step-by-step explanation:

Slope-intercept form is y=mx+b where (x, y) is a point on the linear graph, m is the slope (rise/run), and b is the y-intercept (the y-value at which the graph passes through the y-axis).

Looking at the graph, we can see that the point at which the line crosses the y-axis is (0, 2) which makes it the y-intercept. Thus, the b in the slope-intercept form is 2.

Next, we are looking for the slope of the line. To do this, we can calculate the rise/run of the line by choosing to points on it. Since we already have the point (0, 2), we just need one more.

For example, the point (-4, -1) can be used. The slope can be found by ((y-y)/(x-x)) in which the first y and x values correspond with the first point and that of the second correspond with the second set. So in this case, m = (2-(-1))/(0-(-4)) = 3/4

Plugging in the calculated m and b value in the slope intercept equation, we get y = (3/4)x + 2

PtichkaEL [24]4 years ago

4 0

Answer:

y = 3/4x + 2

Step-by-step explanation:

We only need to find two components,

m and b (slope and y intercept)

Let's find b first because it is easy.

From the line, it passes the y axis through point (0,2) or 2

So b = 2

y = __x + 2

Slope:

Find any two points from the line. (Must be a clear coordinate)

I'll pick,

(-4,-1) and (0,2)

Slope formula:

m = y₂ - y₁ / x₂ - x₁

m = 2 -(-1) / 0 -(-4)

m = 2 + 1 / 0 + 4

m = 3/4

Now that we have the slope, we have completed the slope-intercept form.

y = 3/4x + 2

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Write a cosine function that has an amplitude of 2, a midline of 5 and a period of \frac{3\pi}{4} 4 3π .

kakasveta [241]

Given:

Amplitude = 2

Midline = 5

Period of $\dfrac{3\pi}{4}$ .

To find:

The cosine function.

Solution:

The general cosine function is:

$f(x)=A\cos(Bx+C)+D$ ...(i)

Where, |A| is amplitude, $\dfrac{2\pi}{B}$ is period, $-\dfrac{C}{B}$ is phase shift and D is the mid line.

Period of function is $\dfrac{3\pi}{4}$ . So,

$\dfrac{3\pi}{4}=\dfrac{2\pi}{B}$

$B=2\pi\times \dfrac{4}{3\pi}$

$B=\dfrac{8}{3}$

Substituting $A=2,\ B=\dfrac{8}{3},\ C=0,\ D=5$ in (i), we get

$f(x)=2\cos(\dfrac{8}{3}x+0)+5$

$f(x)=2\cos(\dfrac{8}{3}x)+5$

Therefore, the required cosine function is $f(x)=2\cos(\dfrac{8}{3}x)+5$ .

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3 years ago

Francesca must buy over $55 worth of art supplies to qualify for free shipping

sattari [20]

Answer

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Step-by-step explanation

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3 years ago

I will give brainiest to whoever answers correctly !!

NemiM [27]

Step-by-step explanation:

A) In order to calculate the interest , we can use the following formula :

$P=P_{0}.(1+i)^{t}$

Where P is the interest , P0 is the initial value, i is the interest and t is the time.

So , using P0 =600,i= 0.0005768 and t=27 ,we have :

$P=600.(1+0.0005768)^{27} \\P=600.(1.01569)\\P=609.41$

Calculating only the interest, we have :

$I=609.41-600\\I=9.41\\$

So the interest is $9.41.

B) He paid the final value calculated above, that is , $609.41.

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3 years ago

A cheerleading squad consists of ten cheerleaders of ten different heights. How many ways are there for the cheerleaders to line

Sindrei [870]

Answer:

11340

Step-by-step explanation:

We have 10 cheerleaders of ten different heights. There are two rows each having 5 positions so that five cheerleaders occupy the first row that have height less than the five cheerleaders who occupied the second row.

Therefore, Out of ten cheerleaders, two cheerleaders will be selected out of which the tallest one will occupy the position in the upper row and the second one will occupy in the lower row, therefore these two positions will be occupied in $10C_{2}$ ways. Now, we are left with 8 cheerleaders and following the same path, the next two positions will also be occupied in $8C_{2}$ ways, similarly, following the same path, the number of ways the cheerleaders will occupy the position will be: $10C_{2}$ × $8C_{2}$ × $6C_{2}$ × $4C_{2}$ × $2C_{2}$