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KonstantinChe [14]
3 years ago
13

Write two polynomial functions whose quotient will be the same degree as the divisor.

Mathematics
1 answer:
NemiM [27]3 years ago
8 0

Answer:

f(x) =  2x^2 - x - 1

g(x) = 2x + 1

Step-by-step explanation:

Let the two polynomials be represented with f(x) and g(x);

Since, we have to generate the polynomial ourselves;

I'll make use of the following:

f(x) =  2x^2 - x - 1

g(x) = 2x + 1

Note that; when the result of polynomial division is referred to as quotient;

To get the quotient, we simply divide f(x) by g(x)

\frac{f(x)}{g(x)} = \frac{2x^2 - x - 1}{2x + 1}

Expand the numerator

\frac{f(x)}{g(x)} = \frac{2x^2 - 2x + x - 1}{2x + 1}

\frac{f(x)}{g(x)} = \frac{2x(x - 1) +1(x - 1)}{2x + 1}

Factorize:

\frac{f(x)}{g(x)} = \frac{(2x + 1)(x - 1)}{2x + 1}

Cross out 2x + 1

\frac{f(x)}{g(x)} = x - 1

This implies that, the quotient, Q(x) is

Q(x) = x - 1

<em>Comparing the divisor g(x) and the quotient Q(x), we notice that they have the same degree of 1</em>

<em></em>

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elena-14-01-66 [18.8K]

Answer:

  1. (0, 4)
  2. (-1, 16/ 3)
  3. (-9/ 2, 10)

Step-by-step explanation:

In an ordered pair the term before the comma is the x variable and the term after the comma is the y variable.

1.

4x + 3y = 12 . . . . . .(0, _)

here were given the x variable

finding the other term

4× 0 + 3y = 12

3y = 12

y = 4

therefore the ordered pair is <u>(0, 4) </u>

2.

. . . . . . . (-1, _)

here were given the x variable

4 × -1 + 3y = 12

3y = 12 + 4

3y = 16

y = 16/ 3

ordered pair is <u>(-1, 16/ 3)</u>

3.

. . . . . . . . (_, 10)

here were given the y variable

finding the other term

4x + 3 × 10 = 12

4x + 30 = 12

4x = 12 - 30

4x = -18

dividing both sides by 2

2x = -9

x = -9/ 2

ordered pair is<u> (-9/ 2, 10)</u>

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