Answer:
135°, 63°, 63°, 99°
Step-by-step explanation:
Find attached the diagram used in solving the question.
We would use formula for sum of interior angles to get each exterior angle.
From the diagram, we added additional variables to be able to solve for sum of interior angles.
Sum of angle on a straight line = 180°
a° +15z° = 180°
b° +7z° = 180°
c° +7z° = 180°
d° +11z° = 180°
Where a,b,c and d are interior angles
Sum of interior angles = 180(n-2)
n = number of sides
For quadrilateral, n= 4
a°+b°+c°+d° = 180(n-2)
180-15z +180-7z+180-7z+180-11z = 180(4-2)
720-40z = 180(2)
720 - 360 = 40z
z = 360/40
z = 9
Each exterior angle:
15z = 15×9 = 135°
7z = 7×9 = 63°
7z = 7×9 = 63°
11z = 11×9 = 99°
Answer:
The number of complex roots is 6.
Step-by-step explanation:
Descartes's rule of signs tells you that the number of positive real roots is 0. The number of negative real roots will be at most 2. The minimum value of the left side will be between x=0 and x=-1, but will never be negative. Thus all six roots are complex.
_____
The magnitude of x^3 will exceed the magnitude of x^6 only for values of x between -1 and 1. Since the magnitude of either of these terms will not be more than 1 in that range, the left-side expression must be positive everywhere.
Is that all the information privided? Im tring to figure it out but I feel like im missing something.
Answer:
0.8
hope this is correct!! c: