The formula for calculating compound interest with yearly contributions is:
Balance = X*(1 + Y)^n + Z((1 + Y)^(n + 1) - (1 + Y)/Y)
where the balance is the money earned after n years invested
Y is the interest rate as a fraction
Z is the yearly contribution
X is the starting investment
Therefore the calculation for this example is:
Balance = 1200*(1 + 0.05)^48 + 1200((1.05)^49 - (1.05)/05)
= $249,393.5
Answer:
I think its c
Step-by-step explanation:
Answer:
<u>(-7,-3)</u>
Step-by-step explanation:
step one) solve one equation for x.
y=-3x
-3x/-3=y/-3
x=(-y/3)
step two) plug in x for the other original problem.
y=x-4
y=(-y/3)-4
step three) solve for y.
y=(-y/3)-4
y+4=(-y/3)-4+4
3*(y+4)=(-y/3)*3
3y+12=-y
(3y+12)-3y=-y-3y
12/-4=-4y/-4
y=-3
step four) plug in -3 for y and solve for x.
y=x-4
-3=x+4
-3-4=x+4-4
-7=x
<em>I am in algebra two so you can trust my answer. if you need more help lmk in the comments. happy holidays and stay safe!</em>
I think C is a function since is passed the vertical line test.
