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3 years ago

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Jeff brought a bottle of water for $2.He also brought some hot dogs for $3 each.Jeff did not spend more than $14 on the hot dog

and bottle of water.Which inequality can be used to find h,the number of hot dogs that Jeff could have -------------------------------------------------------------

2 answers:

Gala2k [10]3 years ago

8 0

The answer would be D because 3h + 2 (water) has to be less than or equal to > 14

sveticcg [70]3 years ago

5 0

I believe the answr would be d because 3h+ 2= water and that has to be less than or equal to 14.

hope this helps

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Assume that y varies inversely with x. If y=7 when x=2/3, find y when x=7/3

fgiga [73]

Inverse variation is of the form:

y=k/x, which we can express as:

yx=k we are given the point (2/3, 7) so we can solve for k

7(2/3)=k

14/3=k

y=14/(3x), so when x=7/3

y=(14/3)/(7/3)

y=(14/3)(3/7)

y=2

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3 years ago

What two numbers multiply to 30 and add to -17

victus00 [196]

Answer:

-15 and -2

Step-by-step explanation:

Since a negative times a negative equals a positive, but when added, still stays a negative, the factors must both be negative.

Negative Factors of 30:

-30 + -1 = -31

-15 + -2 = -17

-10 + -3 = -13

-6 + -5 = -11

The two factors of 30 that add up to -17 are -15 and -2.

Hope this helps. Have a nice day.

4 0

3 years ago

13 POINTS- please help me

allsm [11]

Answer:

See explanation

Step-by-step explanation:

16. Two parallel lines are cut by transversal. Angles with measures $(6x+20)^{\circ}$ and $(x+100)^{\circ}$ are alternate exterior angles. By alternate exterior angles, the measures of alternate exterior angles are the same:

$6x+20=x+100\\ \\6x-x=100-20\\ \\5x=80\\ \\x=16$

Then

$(6x+20)^{\circ}=(6\cdot 16+20)^{\circ}=116^{\circ}\\ \\(x+100)^{\circ}=(16+100)^{\circ}=116^{\circ}$

17. Two parallel lines are cut by transversal. Angles with measures $(2x+12)^{\circ}$ and $(3x-22)^{\circ}$ are alternate interior angles. By alternate interior angles, the measures of alternate interior angles are the same:

$2x+12=3x-22\\ \\2x-3x=-22-12\\ \\-x=-34\\ \\x=34$

Then

$(2x+12)^{\circ}=(2\cdot 34+12)^{\circ}=80^{\circ}\\ \\(3x-22)^{\circ}=(3\cdot 34-22)^{\circ}=80^{\circ}$

18. Two parallel lines are cut by transversal. Angles with measures $(6x-7)^{\circ}$ and $(5x+10)^{\circ}$ are alternate exterior angles. By alternate interior angles, the measures of alternate exterior angles are the same:

$6x-7=5x+10\\ \\6x-5x=10+7\\ \\x=17$

Then

$(6x-7)^{\circ}=(6\cdot 17-7)^{\circ}=95^{\circ}\\ \\(5x+10)^{\circ}=(5\cdot 17+10)^{\circ}=95^{\circ}$

19. The diagram shows two complementary angles with measures $2x^{\circ}$ and $56^{\circ}$ . The measures of complementary angles add up to $90^{\circ},$ then

$2x+56=90\\ \\2x=90-56\\ \\2x=34\\ \\x=17$

Hence,

$2x^{\circ}=2\cdot 17^{\circ}=34^{\circ}$

Check:

$34^{\circ}+56^{\circ}=90^{\circ}$

20. Angles $\angle 1$ and $\angle 2$ are vertical angles. By vertical angles theorem, vertical angles are congruent, so

$m\angle 1=m\angle 2\\ \\5x+7=3x+15\\ \\5x-3x=15-7\\ \\2x=8\\ \\x=4$

Hence,

$m\angle 1=(5x+7)^{\circ}=(5\cdot 4+7)^{\circ}=27^{\circ}\\ \\m\angle 2=(3x+15)^{\circ}=(3\cdot 4+15)^{\circ}=27^{\circ}$

21. $\angle 5$ and $\angle 8$ are supplementary. The measures of supplementary angles add up to $180^{\circ},$ so

$m\angle 5+m\angle 8=180^{\circ}\\ \\3x-40+7x-120=180\\ \\10x-160=180\\ \\10x=180+160\\ \\10x=340\\ \\x=34$

Therefore,

$m\angle 5=(3x-40)^{\circ}=(3\cdot 34-40)^{\circ}=62^{\circ}\\ \\m\angle 8=(7x-120)^{\circ}=(7\cdot 34-120)^{\circ}=118^{\circ}\\ \\62^{\circ}+118^{\circ}=180^{\circ}$

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3 years ago

Paula owns a shoe store in Los Angeles. Whenever she orders a new style of shoe, she orders 5 pairs of that style in each of the

suter [353]

She orders 5 pair in 5 different sizes:

5 x 5 = 25 pair

She orders 3 pair in 3 different sizes:

3 x 3 = 9 pair

Total pairs = 25 + 9 = 34 pair.

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3 years ago