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11Alexandr11 [23.1K]
3 years ago
5

4x squared plus 8X plus 3 equals 0

Mathematics
1 answer:
Travka [436]3 years ago
8 0

Answer:

No

4x squared + 8x + 3 =

4x squared: 16x

16x + 8x + 3

add 16 and 8 = 24x + 3 and that's your answer

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Pls help 31b&amp;c. ASAP<br> Thx
Leto [7]

Answer:

b. g(x) = 12x+10

c. x = 9/2

Step-by-step explanation:

b. g(2x+1)=6x+4

   g(2x+1) = 6(2x+1)+4

   g(2x+1) = 12x+6+4

   g(2x+1) = 12x+10

    g(x) = 12x+10

c. g(x) = 64

   12x+10 = 64

     12x = 54

      x = 54/12

      x = 9/2

5 0
3 years ago
The manager of a supermarket wants to obtain information about the proportion of customers who dislike a new policy on cashing c
alex41 [277]

Answer:

n = 61 costumers

Step-by-step explanation:

For calculating the number of costumers he should sample we use the next equation:

n = \frac{z_{1-\alpha/2}^{2}p(1-p)}{E^{2} }

                          Where E is the error that we are prepared to accept, in this  case E = 0.15

How we don't know the value of p, we can estimate it like p = 0.5

∝ = 1-0.98 = 0.02

1-∝/2 = 0.99

z_{0.99} = 2.33

n = \frac{(2.33^{2})(0.5)(1-0.5)}{0.15^{2} }

n = 60.32 costumers

n ≈ 61 costumers

4 0
4 years ago
The sum of two numbers is 23. The first number is 3/20 of the second number. What are the numbers?
Thepotemich [5.8K]

Answer:

Here's what i know:

x + y = 23

3y / 20 =x

 

Here we can use substitution to help find our answer:

y + 3y/20 = 23

20y/20 + 3y/20 = 23

23y/20 = 23

23y = 23 * 20

y = 23 * 20 / 23

y = 20

 

x + 20 = 23

x = 3

6 0
3 years ago
Read 2 more answers
Robert can mow a 600 square lawn in 1 hour and 20 minutes. How many lawns in the same size's can he mow in 8 hours?​
adell [148]
First off change everything to minutes. The 600 is irrelevant in this problem. He can mow this size in 80 minutes. 8 hours is 8x60= 480. 480/80 is 6 and therefore he can mow 6 lawns in this size in time of 8 hours
4 0
2 years ago
Which of the following rational functions is graphed below?
podryga [215]

Answer:

c

Step-by-step explanation:

Oblique Asymptotes

R(x) will have oblique asymptote if it can be represented in the form

1 / (Q)x

4 0
2 years ago
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