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alex41 [277]
3 years ago
7

What is meant by the term "90% confident" when constructing a confidence interval for a mean? Group of answer choices

Mathematics
1 answer:
Harman [31]3 years ago
7 0

Answer:

The question is not complete, below is the complete question:

What is meant by the term 90% confident? when constructing a confidence interval for a mean?

a. If we took repeated samples, approximately 90% of the samples would produce the same confidence interval.

b. If we took repeated samples, approximately 90% of the confidence intervals calculated from those samples would contain the sample mean.

c. If we took repeated samples, approximately 90% of the confidence intervals calculated from those samples would contain the true value of the population mean.

d. If we took repeated samples, the sample mean would equal the population mean in approximately 90% of the samples.

Answer:

The correct answer is:

If we took repeated samples, approximately 90% of the confidence intervals calculated from those samples would contain the true value of the population mean.  (c)

Step-by-step explanation:

a 90% confidence level means that if repeated samples were taken, 9 out of 10 times, the confidence intervals of the sample chosen will be close to the mean (true value), which is a true representation of the population parameter. when using confidence intervals, there are always margins of allowable accuracy, and this is suggested by using standard diviations snd variances.

I attached a simple document to this answer that will give you more insight into confidence intervals used in statistics.

Download pdf
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Answer:

Find below the calculations of the two areas, each with two methods. The results are:

  • Upper triangle:

                     Area=5000\sqrt{3}units^2

  • Lower triangle:

                     Area=14,530m^2

Explanation:

<u>A) Method 1</u>

When you are not given the height, but you are given two sides and the included angle between the two sides, you can use this formula:

           Area=side_1\times side_2\times sin(\alpha)

Where, \alpha is the measure of the included angle.

1. <u>Upper triangle:</u>

          side_1=200units\\ \\ side_2=100units\\ \\ \alpha =60\º\\ \\ Area=200units\times 100units\times sin(60\º)/2\\ \\ Area=5000\sqrt{3}units^2

2. <u>Lower triangle:</u>

         side_1=231m\\ \\ side_2=150m\\ \\ \alpha =123\º\\ \\ Area=231m\times 150m\times sin(123\º)/2\\ \\ Area=14,529.96m^2\approx14,530m^2

<u></u>

<u>B) Method 2</u>

You can find the height of the triangle using trigonometric properties, and then use the very well known formula:

            Area=(1/2)\times base\times height

Use it for both triangles.

3. <u>Upper triangle:</u>

The trigonometric ratio that you can use is:

                    sine(\alpha)=opposite\text{ }leg/hypotenuse

Notice the height is the opposite leg to the angle of 60º, and the side that measures 100 units is the hypotenuse of that right triangle. Then:

         sin(60\º)=height/100units\\ \\ height=sin(60\º)\times100units\\ \\ height=50\sqrt{3}units

Area=(1/2)\times base\times height=(1/2)\times 200units\times 50\sqrt{3}units=5,000\sqrt{3}units^2

3. <u>Lower triangle:</u>

<u />

         sin(180\º-123\º)=height/231m\\ \\ height=sin(57\º)\times 231m\\ \\ height=193.7329m^2<u />

<u />

<u />Area=(1/2)\times base\times height=(1/2)\times 150m\times 193.7329m^2\\\\  Area=14,529.96m^2\approx 14,530m^2<u />

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