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3 years ago

Which infinite geometric series can you NOT find the sum?

Mathematics

1 answer:

Oksanka [162]3 years ago

4 0

Answer: C) 127, 152.4, 182.88, 219.456,...

Step-by-step explanation:

You can only find the sum of an infinite geometric sequence if it converges.

One criterion to see if the series converges is if:

aₙ < aₙ₋₁

This means that, as n increases, the value of the terms decreases.

This means that as n tends to infinity, aₙ tends to zero.

Then we only can find the sum of those series where the terms are decreasing.

in A, B and D the terms are decreasing, then we can find the sum of those 3 series.

Now in the case of C, the terms are increasing, then we can not find the sum of that series.

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What is the best approximation of 6% tax on a $102 purchase? A) $6 B) $12 C) $18 D) $24

larisa [96]

Here, On Approximation, Just consider $102 as $100

Then, 6% of 100 would be: $6

In short, Your Answer would be: Option A

Hope this helps!

6 0

3 years ago

Factorise B square minus 25

GuDViN [60]

Answer: (b+5)(b-5)

Step-by-step explanation:

both b^2 and 25 are square numbers, so square root both of them to give b and 5, then put into brackets with a + and -

3 0

3 years ago

A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each

Nadya [2.5K]

Answer:

$312.5\pi \text{ km}^3\approx 981.75\text{ km}^3$

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

$\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}$ , where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

$\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}$

$\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}$

$\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}$

$\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3$

$\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3$

Therefore, the volume of earth removed to build the three tunnels is $312.5\pi \text{ km}^3\approx 981.75\text{ km}^3$ .

4 0

3 years ago

F(t)=t^2-3t<br> g(t)=2t+1<br> find f(g(t))

statuscvo [17]

Answer:

$f (2t + 1) = 4t^{2} - 2t - 2$

7 0

2 years ago

What is 8777 divided by 456

zimovet [89]

Your answer is 19.25.

8 0

3 years ago