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Assoli18 [71]
4 years ago
5

I need help on these two question

Mathematics
1 answer:
Digiron [165]4 years ago
4 0

3.

A' (30, 5)

B' (40, 5)

C' (40, 0)

D' (30, 0)

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Will mark brainliest question is in attachment
galben [10]

Answer:

m<CBD = 68 degrees

Step-by-step explanation:

Add both of the given angle measures and set them equal to 90 degrees.

4x + 52 + 8x - 10 = 90    Combine like terms

12x + 42 = 90

      - 42  - 42                  Subtract 42 from both sides

12x = 48                           Divide both sides by 12

x = 4

Now plug this into the equation for m<CBD

4(4) + 52       Multiply

16 + 52          Add

68 degrees

If this answer is correct, please make me Brainliest!

8 0
3 years ago
Read 2 more answers
What are the x and y intercepts of -12x + 3y = 48
Mkey [24]
The x intercept is (-4,0) and the y intercept is (0,16).
PLZ GIVE BRAINLIEST!!!
6 0
4 years ago
Read 2 more answers
What is the area, in square units, of the parallelogram shown below? A parallelogram ABCD is shown with height 7 units and base
enot [183]

<u><em>Answer:</em></u>

35 square units

<u><em>Explanation:</em></u>

<u>Area of parallelogram is calculated as follows:</u>

Area = base * height square units

<u>In the given question, we have:</u>

base = 5 units

height = 7 units

<u>Substitute with the givens in the above equation to get the area:</u>

Area of parallelogram = 5 * 7 = 35 square units

Hope this helps :)

3 0
4 years ago
Read 2 more answers
Use the graph of the function. Determine Over what interval(s) the function is positive or negative.
soldier1979 [14.2K]

Answer:

please where is the drawing I mean the graph

6 0
3 years ago
Select the correct answer.
ss7ja [257]

Answer:

B. (2,-5)

Step-by-step explanation:

The vertex of the function can be found in the most lower value that the function can have.

Since we have an ABS function involved we need to analyse it at first

We know that |x| = x if x> 0 and  |x| = -x if x< 0

if we now change x by x-2 (the content of our ABS function involved, we have the following

|x-2| = x-2 if x-2> 0

|x-2| = -x+2 if x-2< 0

Those inequaiities have a common solution

x-2=0, this means that x=2 is the lowest value the ABS(X-2) has and it is equals to zero.

So by evaluating x=2 in the given function we will obtain its vertex.

leading to f(2)=6 |2-2|-5= -5

Hence the point (2,-5) is the vertex of our function

5 0
3 years ago
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