Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
I would say 12 hours and 38 min
90,180 is the same as R so it is
Answer:
Please check the explanation and attached graph.
Step-by-step explanation:
Given the parent function
y = |x|
In order to translate the absolute function y = |x| vertically, we can use the function
g(x) = f(x) + h
when h > 0, the graph of g(x) translated h units up.
Given that the image function
y=|x|+4
It is clear that h = 4. Since 4 > 0, thus the graph y=|x|+4 translated '4' units up.
The graph of both parent and translated function is attache below.
In the graph,
The blue line represents the parent function y=|x|.
The red line represents the image function y=|x| + 4.
It is clear from the graph that the y=|x| + 4 translated '4' units up.
Please check the attached graph.
Answer:
.4!
Step-by-step explanation:
first you divide 20 by 125 and get .16
then you take the square root of .16 and get .4