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Jet001 [13]
3 years ago
12

I will give you brainliest :) Which of the following values are in the domain of the function graphed below? Check all that appl

y.

Mathematics
1 answer:
artcher [175]3 years ago
4 0

The domain is the x value of the graph. I suggest going down the choices and finding which of them is an x value of the function...

Since there are 5 ticks and the 5th tick is 10, we can tell that each tick stands for 2 units. I would label them before we start.

Okay...

-4 cannot be an option, because the x value, -4 is on the 2nd tick mark and the function only goes to the 1st tick.

0 is an option!

5 is not.

-1 is!

4 is!

-2 is!

so we have B D E F

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The triplets, nick, Brian, and dan, exit their preschool classroom every day in a random order. Create an organized list to show
AfilCa [17]

The set of all possibilities is called sample space and is denoted by S.

So, S = {NBD, NDB, BDN, BND, DBN, DNB} and n(S) = 8

and we need to find the probability of NBD

E = {NBD} and n(E) = 1

The probability of an even is defined by p(E) = \frac{n(E)}{n(S)}

Hence,  p(E) = \frac{1}{8}

4 0
3 years ago
What is the answer to 9×(6+7-3)-2​
ZanzabumX [31]

Answer:

88

Step-by-step explanation:

PEMDAS

9*(6+7-3)-2

1) 6+7=13

13-3=10

9*10-2

2)9*10= 90

3)90-2= 88

3 0
3 years ago
Read 2 more answers
Question 31 (Essay Worth 5 points)
slega [8]

Answer:

-12

Step-by-step explanation:

ds/dt = d/dt ( 1-12 t)

ds/dt = -12

When t=2

ds/dt = -12

7 0
2 years ago
Please help mee <br><br> help help
Damm [24]

Answer:

So, to 1 d.p. 7 is about 23% out of 30. (7 of 30=23%)

Step-by-step explanation:

7/30 x 100 =23.3333333333% or 70/3%.

6 0
2 years ago
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

3 0
3 years ago
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