Philip equation
ordered data: 3o(oranges), 3g(green), 6y, 8r, 13b(black, 15b(blue
mean: 8 mode: 3 range: 12
1/2in = 16 mi
2 3/4 in without whole numbers [(denominator ×whole) + numerator] / denominator
4×2 = 8 +3 = 11/4
Find common denominator for 1/2 and 11/4 (common D Is 4)
Multiply 1/2 by 2/2
2/4 in = 16 mi divide this by 2
2/4 ×1/2 = 1/4
16 /2 = 8
1/4 = 8
1/4 goes into 11/4 11 times
Multiply 8 times 11
88 miles (D)
End zone to end zone is = length so his scale is 6 in and in real life it is 360 ft
To find scale divide 360 by 6
1in = 60 ft (B)
160 ft wide
(divide 160 by 60 ft ) fraction
160/60 is a fraction now simplify
16/6
Common factors of both numbers is 2
Simplify by 2
8/3
Make into whole number fraction
3 goes into 8 two times (2×3=6)(2 becomes whole number) while there's is 2 left over( 8 -6=2) (becoming the numerator)
2 2/3 in (B)
120 ft long
80 ft wide
24 in is scale of "long"
Divide 120 by 24
120÷24=5
So 5in in scale equals 1ft in real life
To find width in scale divide 80 by 5
80/5= 16in (A)
If you have any trouble understanding feel free to let me know I will try to explain as best as I can :)
9+3=12
30+20=50
300+100=400
Then add.
12+50+400=462
<span>So 339+123=462</span>
Answer:
The answer should be .25
Step-by-step explanation:
The answer should be .25 because:
- there are 4 places you can score and since you want it to land on 5 and there is only one 5 it counts as a 1
- the since there are 4 in total and you want to land on 1 you get 1/4 the number one standing for there only being one 5 and the 4 standing for the number of places to land on.
-then you convert the 1/4 into a decimal which makes .25
