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Keith_Richards [23]
2 years ago
6

BRAINLYYYY PLUS 100 PointsThe difference between two numbers is 84 and their sum is 278. What are the numbers? Hint( answer is x

=181 and y= 97). Also please note that this is simultaneous equations and show full Woking out
Mathematics
1 answer:
den301095 [7]2 years ago
4 0

Answer:

x = 181 and y = 97

Step-by-step explanation:

let called the first number is x

the second number would be called y

We are given that:

x + y = 278 (1)

x = y + 84 (2)

Let change x in (2) into (1):

y + 84 + y = 278

2y + 84 = 278

Subtract 84 from both side, we got:

2y + 84 - 84 = 278 - 84

2y + 0 = 194

Divide both side by 2, we got:

2y / 2 = 194 / 2

y = 97

Because y = 97 and x + y = 278 so x would equal:

x + 97 = 278

Subtract 97 from both side, we got:

x + 97 - 97 = 278 - 97

x + 0 = 181

x = 181 and y = 97

Hope this helped :3

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FIND THE SURFACE AREA HELP ASAP GET BRAINLISTS
3241004551 [841]

Answer:

\large\boxed{a.\ 7200\pi\ mm^2}

Step-by-step explanation:

The formula of a surface area of a cylinder:

S.A.=2\pi r(r+H)

r - radius

H - height

We have r = 40mm and H = 50mm. Substitute:

S.A.=2\pi(40)(40+50)=80\pi(90)=7200\pi\ mm^2

4 0
3 years ago
What numbers multiply together to get 6 and add together to get 7
aev [14]

It would be 6 and 1 cause:

6 × 1 = 6

6 + 1 = 7

Hope that helps :D

4 0
3 years ago
Read 2 more answers
if a pineapple costs $p and a mango costs $q, write an algebraic expression, in dollars, in terms of p and q for the total cost
nadezda [96]

Answer: 5p + 3q

Explantation: 5 pineapples is going to be multiplied by p, the cost of 1. And 3 mangoes are going to be multiplied by q, the cost of 1. And adding the two totals together gives you the total cost.

7 0
3 years ago
Machine A can fill an order of widgets in a hours. Machine B can fill the same order of widgets in b hours. Machines A and B beg
ycow [4]

Answer:

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Step-by-step explanation:

Consider the provided information.

Machine A can fill an order of widgets in a hours. Machine B can fill the same order of widgets in b hours.

Thus, in 1 hr machine A's work is 1/a and machine B's work is 1/b.

We need to find whether the Machine A's rate the same as that of Machine B?

Statement 1: Machines A and B finish the order at exactly 4:48 p.m.

Total time, A and B worked = 4:48 = 4+\frac{48}{60} hrs = 4+\frac{4}{5} hrs= \frac{24}{5} hours

Thus, \frac{1}{a}+\frac{1}{b} = \frac{5}{24}

Let say Machine A's rate the same as that of Machine B

\frac{1}{a}+\frac{1}{a} = \frac{5}{24}\\\\\frac{2}{a} = \frac{5}{24}\\\\a = \frac{48}{5}

It is given that a and b are even integers, but \frac{48}{5} is not an even integer.

Hence, Machine A's rate is not same as that of Machine B.

Therefore, statement (1) ALONE is sufficient.

Statement 2: (a + b)^2 = 400

(a+b)^2 = 400\\a+b=20

There are many possible case in which a and b are even integer and there sum is 20.

If a = b = 10 (both even), then Machine A's rate is same as that of Machine B.

if a = 6 and b = 14 (both even), then Machine A's rate is not same as that of Machine B.

Therefore, No unique answer with statement 2.

Hence, statement 2 alone is not sufficient.

6 0
3 years ago
HELP I HAVE NO IDEA WHATS GOING ON PLS HELP
Eduardwww [97]

Answer:

0.182 probability that the Yankees will win when they score fewer than 5 runs

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem:

When the Yankees score less than 5 runs, either they win, or they lose. The sum of these probabilities is 1.

Probability they lose:

Event A: Scoring fewer than 5 runs.

Event B: Losing

The probability that the Yankees will score 5 or more runs in a game is 0.56.

So 1 - 0.56 = 0.44 probability the Yankees score fewer than 5 runs.

This means that P(A) = 0.44

The probability that the Yankees lose and score fewer than 5 runs is 0.36.

This means that P(A \cap B) = 0.36

Then the probability they lose is:

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.36}{0.44} = 0.818

Probability they win:

p + 0.818 = 1

p = 0.182

0.182 probability that the Yankees will win when they score fewer than 5 runs

3 0
3 years ago
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