Question

Solve the inequality (question 30 please, already solved others)

Answer 1

Answer:

n ≤ 32

Step-by-step explanation:

Given

$\frac{1}{4}$ n + 12 ≥ $\frac{3}{4}$ n - 4

Subtract $\frac{1}{4}$ n from both sides

12 ≥ $\frac{1}{2}$ n - 4 ( add 4 to both sides )

16 ≥ $\frac{1}{2}$ n ( multiply both sides by 2 )

32 ≥ n, hence

n ≤ 32

Answer 2

$\bf \cfrac{1}{4}n+12 \geqslant \cfrac{3}{4}n-4\implies \cfrac{1}{4}n+16 \geqslant \cfrac{3}{4}n\implies 16\geqslant \cfrac{3n}{4}-\cfrac{1n}{4}\implies 16\geqslant \cfrac{3n-1n}{4} \\\\\\ 16\geqslant\cfrac{2n}{4}\implies 16\geqslant \cfrac{n}{2}\implies 32 \geqslant n$