Answer:
<h2>There are 13 quarters, 5 nickels and 20 dimes.</h2>
Step-by-step explanation:
Givens
- Max has $5.50.
- He has eight more quarters than he does nickels.
- He had four times as many dimes as he has nickels.
From these statements, we can deduce algebraical expressions to solve the problem. Let's call 
quarters, 
nickels and 
dimes.
(8 more quarters than nickels)
(he has four times as many dimes as he has nickels).
(Max has a total of $5.50, one quartes is $0.25, one nickel is $0.05 and one dime is $0.10).
Let's replace the first two expressions into the third equation
There are 5 nickels.
Now, we use this value to find the number of quarters
There are 13 quarters.
Also, 
There are 20 dimes.
Therefore, there are 13 quarters, 5 nickels and 20 dimes.
Answer:
This can be found by using the permutations and combinations formuals.
Combinations being the C equation and Permutations being the P equation.
Explanation:
A permutation is used for the list of data (where the order of the data matters) and the combination is used for a group of data (where the order of data doesn't matter).
Answer:
Im a soccer goalie too
Step-by-step explanation: 21/25, 0.84, 84%
Answer:
$76.8
Step-by-step explanation:
As, So 20% of 64 will be the markup price.
So 20/100 x 64 = $12.8
Now Markup price = $12.8
And The retail price = markup price + original price = $12.8 + $64 = $76.8
The greatest common factor is 12 because 12 times 3 is 36 and 12 times 7 is 84.
Hope this helps! :)
