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3 years ago

PLEASEEEEE HELP ME

Mathematics

2 answers:

Nadya [2.5K]3 years ago

4 0

c. 44.25 trust me I just took the test.

Drupady [299]3 years ago

4 0

Answer:

The correct option is C.

Step-by-step explanation:

The general form of linear regression equation is

$y=a+bx$ .... (1)

where,

$b=\frac{\sum_{i=1}^nx_iy_i-n\overline{x}\overline{y}}{\sum_{i=1}^nx_i^2-n\overline{x}^2}$

$a=\overline{y}-b\overline{x}$

Using the graphing calculator, we get

$a=0.0142857$

$b=2.01071$

Substitute the values of a and b in equation (1).

$y=0.0142857+2.01071x$

The equation of line of best fit is y=0.0142857+2.01071x, where x is number of years and y is height of trees.

Substitute x=22 to find the height of trees after 22 years.

$y=0.0142857+2.01071(22)$

$y=44.2499057$

$y=44.25$

The height of trees after 22 years is 44.25 ft. Therefore the correct option is C.

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If x equals 5 what is 72+72+18x+9+18x+9

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Answer:

342

Step-by-step explanation:

x=5

72+72+18(5)+9+18 (5)+9=342

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2 years ago

2) At the store Julie bought a shirt for $23.97, which was 25% off the original price. Which of these should she use to find x,

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Answer:

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Step-by-step explanation:

The total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75.

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3 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

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