Solve 3kx + 24 = 9kx for x. A. x= 4/k B. x= -2/k C. x= 2/k D. x= -4/k

Is it possible to have the same lower quartile as the minimum in a box plot?

Natalka [10]

No, bc the lower quartile should be in between the minimum and middle quartile(median) Hoped this helped!

6 0

4 years ago

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Domain: Range: Increasing: Decreasing:

mihalych1998 [28]

Answer:

Domain- -2>x<2

Range- [4,∞)

Increasing-[∞,4]

Decreasing-[4,∞]

3 0

3 years ago

ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)

Delicious77 [7]

$remember$
$ln(x)=log_e(x)$
$and$
$log_x(a)-log_x(b)= log_x( \frac{a}{b} )$
$and$
$log_a(b)=c$ means $a^c=b$
$and$
$blog(a)=log(a^b)$

$so$

$ln(y+1)-ln(y)=1+3ln(x)$
$ln( \frac{y+1}{y} )=1+ln(x^3)$

$minus$ $ln(x^3)$ $from$ $both$ $sides$

$ln( \frac{y+1}{y}-ln(x^3) )=1$
$ln( \frac{y+1}{yx^3})=1$
$log_e( \frac{y+1}{yx^3})=1$

$translate$

$e^1=\frac{y+1}{yx^3}$
$e=\frac{y+1}{yx^3}$

$times$ $both$ $sides$ $by$ $yx^3$

$eyx^3=y+1$

$minus$ $y$ $from$ $both$ $sides$

$eyx^3-y=1$
$y(ex^3-1)=1$

$divide$ $both$ $sides$ $by$ $(ex³-1)$

$y= \frac{1}{ex^3-1}$

6 0

3 years ago

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ASAP answer please. First is brainliest.

chubhunter [2.5K]

Answer:

A. d + c = 50

4d + 2c = 174

Step-by-step explanation:

Mark me brainliest

6 0

4 years ago

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A company makes wax candles in the shape of a solid sphere. Suppose each candle has a diameter of 15 cm. If

jekas [21]

We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.

To solve our given problem, we will divide total volume of wax by volume of one candle.

Volume of each candle will be equal to volume of sphere.

$V=\frac{4}{3}\pi r^3$ , where r represents radius of sphere.