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OverLord2011 [107]
3 years ago
15

Consider circle with diameter DE. E(13,11) D(-3,3)

Mathematics
1 answer:
Mariulka [41]3 years ago
7 0
The length of DE 21.26029163 units
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The base of a rectangular prism has an area of 13 2/3, and the height of the prism is 8 5/6. What is the volume of the prism? Be
Fed [463]

Answer:

120 \frac{13}{18}

Step-by-step explanation:

<em><u>The formula for finding the volume of a prism is:</u></em>

V = Bh

<em><u>You have to convert 13 </u></em>\frac{2}{3}<em><u> into an improper fraction, like so:</u></em>

\frac{41}{3}

<em><u>Convert the other:</u></em>

<em><u /></em>\frac{53}{6}

<em><u>Multiply:</u></em>

<em><u /></em>\frac{41}{3} · \frac{53}{6} = \frac{2173}{18}

<em><u>Convert to mixed fraction:</u></em>

120 \frac{13}{18}

6 0
3 years ago
Ella completed 3/8 of a puzzle during recess on Tuesday. Joy completed two six of the same puzzle during recess on Wednesday. ho
gavmur [86]
Well u have to make the denominator the same so u multiply 3/8 by 3 and get 9/24, then multiple 2/6 by three and get 8/24. Add them, 9/24+8/24 and u get 17/24
6 0
3 years ago
13....................
Mashcka [7]

13.

(a)

y=-5x^2+21x-3

for x = 2:

y=-5(2)^2+21(2)-3=-20+42-3=19

for x = 5

y=-5(5)^2+21(5)-3=-125+105-3=-23

(b)

The graph is:

(c)

Using the graph:

\begin{gathered} x=1.8,y=18.6 \\ x=0.548,y=7 \\ x=3.65,y=7 \end{gathered}\begin{gathered} x=1.8 \\ y=-5(1.8)^2+21(1.8)-3=-16.2+37.8-3=18.6 \end{gathered}\begin{gathered} y=7 \\ -5x^2+21x-3=7 \\ -5x^2+21x-10=0 \end{gathered}

Using the quadratic formula:

\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-21\pm\sqrt[]{21^2-4(-5)(-10)}}{2(-5)} \\ x=\frac{-21\pm\sqrt[]{241}}{-10} \\ x=0.54758 \\ or \\ x=3.6524 \end{gathered}

6 0
1 year ago
What is the equation of the line that contains the points (2,6) and (-2,4)
suter [353]

Answer:

y =1 /2 x+ 5

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Integers<br>53 + (-26 )​
-BARSIC- [3]
<h2>✨ Question ✨</h2>

53 + (-26 )

<h2>✨ Answer ✨</h2>

\:  \:  \:  \:  \: \:  \:  \:  \:   \purple{ \boxed{ \boxed{ \huge{ \tt{ \: 37 \: }}}}}

6 0
2 years ago
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