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2 years ago

Which of the following has the largest value?

Mathematics

1 answer:

Westkost [7]2 years ago

5 0

Answer:

1/2

Step-by-step explanation:

1/2 = 0.50 has a larger value than 0.09 or 0.35 (=35%).

The largest value is 1/2.

_____

Decimal numbers are compared left to right. Comparisons are made of digits having the same number place, so tenths are compared to tenths (for starters). Here, that means you're comparing 5 tenths to 0 tenths to 3 tenths. 5 wins.

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In a newspaper poll concerning violence on television, 589 people were asked, "What is your opinion of the amount of violence on

abruzzese [7]

Answer:

(a) $P(Y'|M)\approx 0.3297$

(b) $P(Y|M')\approx 0.8323$

Step-by-step explanation:

Given table is

Yes No Don't Know Total

Men 162 92 25 279

Women 258 41 11 310

Total 420 133 36 589

According the the conditional probability, if A and B are two event then

$P(A|B)=P(\frac{A}{B})=\frac{P(A\cap B)}{P(B)}$

We need to find the following probabilities.

Let Y is the event "saying yes," and M is the event "being a man."

(a)

$P(Y'|M)=\frac{P(Y'\cap M)}{P(M)}$

$P(Y'|M)=\frac{\frac{92}{589}}{\frac{279}{589}}$

$P(Y'|M)=\frac{92}{279}$

$P(Y'|M)=0.329749103943$

$P(Y'|M)\approx 0.3297$

(b)

$P(Y|M')=\frac{P(Y\cap M')}{P(M')}$

$P(Y|M')=\frac{\frac{258}{589}}{\frac{310}{589}}$

$P(Y|M')=\frac{258}{310}$

$P(Y|M')=0.832258064516$

$P(Y|M')\approx 0.8323$

(c)

$P(Y'|M')=\frac{P(Y'\cap M')}{P(M')}$

$P(Y'|M')=\frac{\frac{41}{589}}{\frac{310}{589}}$

$P(Y'|M')=\frac{41}{310}$

$P(Y'|M')=0.132258064516$

$P(Y'|M')\approx 0.1323$

5 0

2 years ago

Y = 3 X intercept : ________ Y intercept : ________ Slope: ________

erik [133]

Y = 3 will be a straight, horizontal line on 3. It will only touch the y-axis since there's no x. So, the X-Intercept doesn't exist, the Y-Intercept will be (0,3), and the slope of the line is 0.

8 0

2 years ago

A bowl has 9 green grapes and 13 grapes. Henry randomly chooses a grape, and eats it, and then choose a another grape What is th

Sunny_sXe [5.5K]

Answer:

$\frac{72}{462}$ or $\frac{12}{77}$ (simplified)

Step-by-step explanation:

Based on the information provided within the question it can be said that in order to calculate the probability of both grapes being green we need to find the probability of each grape being green separately and then multiply those probabilities together

In the first choice, there are a total of 22 grapes (9+13), 9 of which are green. Therefore the probability of the first chosen grape being green is $\frac{9}{22}$

In the second choice,since we removed one grape there is now a total of 21 grapes (22-1), 8 of which are green. Therefore the probability of the second chosen grape being green is $\frac{8}{21}$