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3 years ago

Write the equation of the line, in standard form that has an x intercept at (3,0) and y

Mathematics

1 answer:

Nataly [62]3 years ago

6 0

x intercept=a=3
y intercept=b=-2

We need the normal form first

$\\ \rm\bull\rightarrowtail \dfrac{x}{a}+\dfrac{y}{b}=1$

$\\ \rm\bull\rightarrowtail \dfrac{x}{3}-\dfrac{y}{2}=1$

Multiply by 6to bring standard form

$\\ \rm\bull\rightarrowtail 2x-3y=1$

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How many times smaller is 2 × 10-3 than 4 × 10-2? PLEASE HELP

NNADVOKAT [17]

<h2>The required "option A) 20" is correct.</h2>

Step-by-step explanation:

Let x be the smaller than 4 × $10^{-2}$ .

To find, the number of times smaller is 2 × $10^{-3}$ than 4 × $10^{-2}$ = ?

∴ x = $\dfrac{4\times 10^{-2}}{2\times 10^{-3}}$

= 2 × $10^{-2}$ × $10^{3}$

Using the identity,

$a^{m}=\dfrac{1}{a^{-m}}$

= 2 × $10^{-2+3}$

Using the identity,

$a^{m} \timesa^{n}=a^{m+n}$

= 2 × $10^{1}$

= 2 × 10

= 20

Thus, the required "option A) 20" is correct.

6 0

3 years ago

Determine the domain and range for the function m(x)=-x^2+4x-3

jasenka [17]

Answer:

domain is all real numbers

range is y is less than or equal to 1 (it is a downward parabola)

4 0

3 years ago

Three nurses attended a seminar for two days. The travel expenses for each nurse were $982. Additional expenses per nurse per da

Vlad [161]

<span>You can just add up the "additional expenses", multiply that by 2 (for the 2 days) and then multiply that by 3 (for the 3 nurses) Then multiply 982 by 3 (for 3 nurses) and all the numbers up

</span><span>I got $8526 as an answer,
</span><span>
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

</span>

7 0

3 years ago

A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo

never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.