Answer:
The critical value for this hypothesis test is 6.571.
Step-by-step explanation:
In this case the professor wants to determine whether the average number of minutes that a student needs to complete a statistics exam has a standard deviation that is less than 5.0 minutes.
Then the variance will be,
The hypothesis to determine whether the population variance is less than 25.0 minutes or not, is:
<em>H</em>₀: The population variance is not less than 25.0 minutes, i.e. <em>σ²</em> = 25.
<em>Hₐ</em>: The population variance is less than 25.0 minutes, i.e. <em>σ²</em> < 25.
The test statistics is:

The decision rule is:
If the calculated value of the test statistic is less than the critical value,
then the null hypothesis will be rejected.
Compute the critical value as follows:

*Use a chi-square table.
Thus, the critical value for this hypothesis test is 6.571.
The scale for the model length of the fuselage obtained by taking the ratio of the model length and the actual length is 0.125
Actual Length of fuselage = 170 feets
Length of fuselage on model = 21.25
<u>To obtain the scale of the model, we take the ratio of the model length and the actual length</u> :
- Model length / Actual length
- 21.25 feets / 170 feets = 0.125
Therefore, the scale for the model length of the fuselage is 0.125
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Answer:
4 jackets have hoods
Step-by-step explanation:
Simply take the 8 with hoods and divide 32 by 8.
Step-by-step explanation:
Sub in your values
4-4(-3)/2
=4 + 12 /2
=4+ 6
=10