The astronomer has to choose 3 star images out of 8.This is a problem of combinations. This can be expressed as 8C3 i.e. combination of 8 objects taken 3 at a time.
This means, if 8 images are nearby the astronomer will have 56 choices <span>
of the three stars.</span>
Answer:
The gcd(259, 621) = 1 and gcd(108, 156) = 12
Step-by-step explanation:
The Euclidean algorithm solves the problem:
Given integers a, b, find d = gcd(a,b)
These are the steps of the Euclidean algorithm:
- Let a = x, b = y.
- Given x, y use the division algorithm to write
where q is quotient and r is the remainder - If r = 0, stop and output y; this is the gcd of a, b.
- if r ≠ 0, replace (x, y) by (y,r). Go to step 2.
These are the steps for the division algorithm:
- Subtract the divisor from the dividend repeatedly until we get a result that lies between 0 and the divisor
- The resulting number is known as the remainder, and the number of times that the divisor is subtracted is called the quotient.
To find the greatest common divisor of 621 and 259 by the Euclidean algorithm you need to:
- Divide 621 by 259, applying the division algorithm you get
next you need to write the expression 
- Divide 259 by 103 to write
- Divide 103 by 53 to write
- Divide 53 by 50 to write
- Divide 50 by 3 to write
- Divide 3 by 2 to write
- Divide 2 by 1 to write
The greatest common divisor of 621 and 259 is 1
To find the greatest common divisor of 156 and 108 by the Euclidean algorithm you need to:
- Divide 156 by 108 to write
- Divide 108 by 48 to write
- Divide 48 by 12 to write
The greatest common divisor of 156 and 108 is 12
Answer: 45.725 ( i think)
Step-by-step explanation: 2.325 + 27.9 + 15.50
I uploaded the answer to a file hosting. Here's link:
tinyurl.com/wpazsebu
Product of a number and four is 4x
<span>12 more than that is 12+4x </span>
<span>fewer than 60 </span>
<span>12 + 4x < 60</span>
