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AVprozaik [17]
4 years ago
8

Help on the equation.

Mathematics
1 answer:
nadya68 [22]4 years ago
8 0
You plug in 3 where you see x and 4 where you see y

3*3+1/4*4^2
9+1/4*16
9+4
13

Remember to follow PEMDAS (order of operations)
parenthesis, exponents, multiply, divide, add, subtract<span />
You might be interested in
Brian’s school locker has a three-digit combination lock that can be set using the numbers 5 to 9 (including 5 and 9), without r
andreev551 [17]
The possible digits are: 5, 6, 7, 8 and 9. Let's mark the case when the locker code begins with a prime number as A and the case when <span>the locker code is an odd number as B. We have 5 different digits in total, 2 of which are prime (5 and 7).

First propability:
</span>P_A=\frac{2}{5}=40\%
<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with 5, 7 or 9 (three of five digits).

Second probability:
</span>P_B=\frac{3}{5}=60\%
5 0
3 years ago
What is the approximate volume of a cone with a height of 6mm and radius of 18 use 3.14 to approximate pi
Mandarinka [93]

Hello from MrBillDoesMath!

Answer:

2035.8  (approximately)

Discussion:

The volume of a cone or radius r and height h is given by the formula:

Volume = (1/3) Pi * r^2 * h. In our case this is:

V = (1/3) Pi * (18)^2 * 6

   =(1/3) Pi * 324 * 6                      => 324/3 = 108

   = 108 * 6 Pi                                 => 108 *6 = 648

   = 648 * Pi                                    => approximating Pi by 3.14

   = 648 * 3.14

   = 2035.8  (approximately)

Thank you,

MrB

5 0
3 years ago
Add. write your answer in simplest form.<br> -4 _/135 + 7 _/15
Zarrin [17]

\huge\quad\qquad\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  - 4 \sqrt{135} + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 4 \sqrt{5 \times3 \times 3 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \:( - 4 \times 3) \sqrt{5 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 12 \sqrt{15 }  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 5 \sqrt{15}

7 0
3 years ago
Solve for x. Round to the nearest tenth of a degree, if necessary.​
MissTica

Answer:

x ≈ 54.8°

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan x = \frac{opposite}{adjacent} = \frac{PQ}{QR} = \frac{7.1}{5} , then

x = tan^{-1} (\frac{7.1}{5} ) ≈ 54.8° ( to the nearest tenth )

4 0
3 years ago
What is the area of the rectangle?
allsm [11]

Answer:

6300

Step-by-step explanation:

79.372539331952

6,300.00000000195

26.45751311065 × 3

79.37253933195

10 × 70

700

√(700)

26.45751311065

7 0
3 years ago
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