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Oksanka [162]
3 years ago
5

Solve . . . 6/14=7/x-3

Mathematics
1 answer:
inn [45]3 years ago
7 0

Answer:   x

=

19

1

3

Step-by-step explanation:

6

14

=

7

x

−

3

Rewrite the equation as

7

x

−

3

=

6

14

.

7

x

−

3

=

6

14

Cancel the common factor of

6

and

14

.

Tap for more steps...

7

x

−

3

=

3

7

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

7

⋅

7

=

(

x

−

3

)

⋅

3

Solve the equation for

x

.

Tap for more steps...

x

=

58

3

The result can be shown in multiple forms.

Exact Form:

x

=

58

3

Decimal Form:

x

=

19.

¯

3

Mixed Number Form:

x

=

19

1

3

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miskamm [114]

Answer:

A)   2704 hands

B)   16 hands

C)   144 hands

D)   384 hands

E)   208 hands

F)   400 hands

Step-by-step explanation:

See the attached file for explanation

8 0
3 years ago
the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 58 in, find its length and width
dolphi86 [110]

Answer:

  • Length = 17 inches

  • Width = 12 inches

⠀

Step-by-step explanation:

⠀

As it is given that, the length of a rectangle is 5 in longer than its width and the perimeter of the rectangle is 58 in and we are to find the length and width of the rectangle. So,

⠀

Let us assume the width of the rectangle as x inches and therefore, the length will be (x + 5) inches .

⠀

Now, <u>According to the Question :</u>

⠀

{\longrightarrow \qquad { \pmb{\frak {2 ( Length + Breadth )= Perimeter_{(Rectangle)} }}}}

⠀

{\longrightarrow \qquad { {\sf{2 ( x + 5 + x )= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{2 ( 2x + 5  )= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x + 10= 58 }}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x = 58  - 10}}}}

⠀

{\longrightarrow \qquad { {\sf{ 4x = 48}}}}

⠀

{\longrightarrow \qquad { {\sf{ x =  \dfrac{48}{4} }}}}

⠀

{\longrightarrow \qquad{ \underline{ \boxed { \pmb{\mathfrak {x = 12}} }}} }\:  \:  \bigstar

⠀

Therefore,

  • The width of the rectangle is 12 inches .

⠀

Now, We are to find the length of the rectangle:

{\longrightarrow \qquad{ { \frak{\pmb{Length = x + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 12 + 5 }}}}}

⠀

{\longrightarrow \qquad{ { \frak{\pmb{Length = 17}}}}}

⠀

Therefore,

  • The length of the rectangle is 17 inches .

⠀

8 0
2 years ago
Read 2 more answers
Solve by setting up a system of linear equations with 2 variables and 2 unknowns. Two hundred seventy six students enrolled in a
jeyben [28]

Let us say ,

x=number of students who passed

y=number of students who failed

total number of students =276

x+y=276..................(1)

We are given 5 times the number of students passed as failed.

x=5y.............(2)

plugging value of x from (2) in (1),

5y+y=276

6y=276

y=46

x=5y=46*5=230

x=number of students who passed=230

4 0
3 years ago
The cost of flying a passenger plane from point A to point B is ​$70 comma 00070,000. The airline flies this route four times pe
Vladimir [108]

Answer:

I. $291.67 per passenger

II. $583.33 per passenger

Step-by-step explanation:

The cost of flying the passenger plane from A to B is $70,000.

If the Capacity of the plane is 240 people.

(I)At 7A.M and 4P.M., the average cost per passenger is given as:

Average Cost=Total Cost/Number of Passengers

=70000/240=$291.67 per passenger

(II)At 10AM and 1PM, the flight is only half full, it has 120 passengers.

Average Cost = 70000/120=$583.33 per passenger

4 0
4 years ago
Read 2 more answers
Can anyone do this ??
Ilya [14]

Answer:

I think is A tell me if I am wrong

Step-by-step explanation:

7 0
4 years ago
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