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3 years ago

Tommy used a straightedge and a compass to construct a square inside circle C, as shown.

Mathematics

1 answer:

myrzilka [38]3 years ago

5 0

Answer:

The correct options are;

A. Construct a perpendicular bisector of the diameter AB

D. Use the compass to draw a circle centered at point C

E. Use the compass to draw two arcs of the same radius centered at point C

F. Use the straightedge to draw diameter AB of the circle

G. Use the straightedge to draw lines connecting the endpoints of the two diameters

Step-by-step explanation:

To draw an inscribed square of a circle, the circle is first constructed. The diameter of the circle is drawn with a straight edge to find the first two vertices of the intended inscribed square. The perpendicular bisector of the diameter is then drawn intersecting the circumference to provide the other two vertices of the square.

The straightedge is then used to draw lines that connect the endpoints of the two diameters to form the inscribed square of the circle.

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If G(x) = 3x + 1, then G^-1(1) is

NISA [10]

One way in which to do this problem is to find the inverse function of G(x) first. Another, faster, method is to look at G(x) = 3x + 1. Find the x value for which y = 1:

1 = 3x + 1. Then x must equal 0. If (0, 1) satisfies G(x) = 3x + 1, then (1, 0) satisfies the inverse function of G(x) = 3x + 1.

Thus, the value of the inverse function with input 1 is 0.

Step 1: Replace "G(x)" with y.

Step 2: Solve the resulting equation for x.

Step 3: Replace x with y and y with x.

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Step 4: Replace this "y" with G (x).

Now replace "x" with "1".

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4 years ago

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KiRa [710]

Ummmmmmm try using those things that help ppl with math

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3 years ago

What is the sum of the geometric series

lbvjy [14]

If $S$ denotes the sum of the first $n$ terms of a geometric series with first term $a$ and common ratio $r$ , then

$S=a+ar+ar^2+\cdots+ar^{n-3}+ar^{n-2}+ar^{n-1}$
$rS=ar+ar^2+ar^3+\cdots+ar^{n-2}+ar^{n-1}+ar^n$
$\implies S-rS=a+(ar-ar)+(ar^2-ar^2)+\cdots+(ar^{n-1}-ar^{n-1})-ar^n$
$\implies (1-r)S=a(1-r^n)$
$\implies S=a=\dfrac{1-r^n}{1-r}$

Using summation notation, you have

$S=\displaystyle\sum_{x=1}^nar^{x-1}=\sum_{x=0}^{n-1}ar^x=a\dfrac{1-r^n}{1-r}$

In this case, you have $a=2$ , $r=\dfrac12$ , and $n=16$ . So the value of the sum is

$\displaystyle\sum_{x=0}^{15}2\left(\frac14\right)^x=2\dfrac{1-\left(\frac14\right)^{16}}{1-\frac14}\approx2.67$

Rounded to the nearest whole number, the answer would be 3.

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4 years ago

Read 2 more answers

What is the inverse of function f? F(X) = square root of x +7

katrin2010 [14]

Answer: $f^{-1} (x)=x^{2} -7$

Step-by-step explanation:

To find the inverse of a function replace f(x) with x and the original x with y

$f(x)=\sqrt{x+7} \\x=\sqrt{y+7}$

Now we can solve for y

Square both sides so we can cancel out the root

$x=\sqrt{y+7}\\x^{2} =\sqrt{y+7}^{2} \\x^{2} =y+7$

Now subtract 7 from both sides

$x^{2} =y+7\\x^{2} -7=y+7-7\\x^{2} -7=y$

Now replace y with the inverse of f(x), $f^{-1} (x)$

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3 years ago

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PLZ HELP 30 POINTS 1 QUESTION WILL MARK AS BRAINLIEST IF CORRECT

horrorfan [7]

The answer would be (B) y = 2x - 2 because when you substitute all of the points in terms of y and x everything fits accordingly. For example, if plugged in the coordinates for the first point you would get: y = 2(1.5) - 2. When you solve for y, you get 1 which is in fact the y-coordinate. Hope this helps!

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3 years ago