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3 years ago

Solve 3(x + 5) = 2x + 35

Mathematics

2 answers:

kumpel [21]3 years ago

6 0

The incorrect step is Step 2. You were supposed to subtract 2x and not add it.

elena55 [62]3 years ago

5 0

Step 2 and all that follows is wrong because it should equal 20

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9.3-t=-1.6 what is the value of t?

vovangra [49]

Answer:

t = 10.9

Step-by-step explanation:

9.3-t=-1.6

Subtract 9.3 from each side

9.3-t-9.3=-1.6-9.3

-t =-10.9

Multiply each side by -1 to find t

t = 10.9

8 0

3 years ago

Read 2 more answers

Can someone help me with the attached problem it’s for geometry, it’s urgent!

Sedaia [141]

I am sorry but I cannot see the picture properly, can you add another photo? Sorry for the inconvenience.

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3 years ago

10 normal six sided dice are thrown.Find the probability of obtaining at least 8 failuresif a success is 5 or 6.

erastova [34]

Answer:

0.2992 = 29.92% probability of obtaining at least 8 failures.

Step-by-step explanation:

For each dice, there are only two possible outcomes. Either a failure is obtained, or a success is obtained. Trials are independent, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A success is 5 or 6.

A dice has 6 sides, numbered 1 to 6. Since a success is 5 or 6, the other 4 numbers are failures, and the probability of failure is:

$p = \frac{4}{6} = 0.6667$

10 normal six sided dice are thrown.

This means that $n = 10$

Find the probability of obtaining at least 8 failures.

This is:

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{10,8}.(0.6667)^{8}.(0.3333)^{2} = 0.1951$

$P(X = 9) = C_{10,9}.(0.6667)^{9}.(0.3333)^{1} = 0.0867$

$P(X = 10) = C_{10,10}.(0.6667)^{10}.(0.3333)^{0} = 0.0174$

Then

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) = 0.1951 + 0.0867 + 0.0174 = 0.2992$

0.2992 = 29.92% probability of obtaining at least 8 failures.

8 0

3 years ago

3. WHAT IS THE END BEHAVIOR?SHOW WORK.<br><br> - 10x -x+ 2

nekit [7.7K]

Answer:

Step-by-step explanatio

−10x−x+2

=−10x+−x+2

=(−10x+−x)+(2)

=−11x+2

Answer:

=−11x+2

3 0

3 years ago

Represent each sum as a single rational number.<br> 7 + (1/9)

Nady [450]

Answer:

Do u have a picture of it

Step-by-step explanation:

5 0

3 years ago