Answer:
By absorbing energy levels
Explanation:
The given question is incomplete. The complete question is as follows.
A 0.6-m3 rigid tank is filled with saturated liquid water at 135°C. A valve at the bottom of the tank is now opened, and one-half of the total mass is withdrawn from the tank in liquid form. Heat is transferred to water from a source of 210°C so that the temperature in the tank remains constant. Assume the surroundings to be at 25°C and 100 kPa. Determine the amount of heat transfer.
Explanation:
First, we will determine the initial mass from given volume and specific volume as follows.
=
= 558.14 kg
Hence, the final mass and mass that has left the tank are as follows.
=
= 279.07 kg
Now, the final specific volume is as follows.
=
= 0.00215
Final quality of the mixture is determined actually from the total final specific volume and the specific volumes of the constituents for the given temperature are as follows.
=
=
Hence, the final internal energy will be calculated as follows.
=
= 571.06 kJ/kg
Now, we will calculate the heat transfer as follows.
Q =
= 1113.5 kJ
Thus, we can conclude that amount of heat transfer is 1113.5 kJ.
Answer:
0.7g of HCl
Explanation:
First, let us write a balanced equation for the reaction between HCl and Al(OH)3.
This is illustrated below:
Al(OH)3 + 3HCl —> AlCl3 + 3H2O
Next, let us obtain the masses of Al(OH)3 and HCl that reacted together according to the equation. This can be achieved as shown below:
Molar Mass of Al(OH)3 = 27 + 3(16+1)
= 27 + 3(17) = 27 + 51 = 78g/mol.
Molar Mass of HCl = 1 + 35.5 = 36.5g/mol
Mass of HCl from the balanced equation = 3 x 36.5 = 109.5g
Now we can obtain the mass of HCl that would react with 0.5g of Al(OH)3. This can be achieved as follow:
Al(OH)3 + 3HCl —> AlCl3 + 3H2O
From the equation above,
78g of Al(OH)3 reacted with 109.5g of HCl.
Therefore, 0.5g of Al(OH)3 will react with = (0.5 x 109.5)/78 = 0.7g of HCl
The balanced NET ionic equation for the reaction is CrBr₃(aq) + Na₃PO₄(aq) ==> CrPO₄(s) + 3NaBr(aq)
<h3>What is a balanced Ionic equation ?</h3>
In a balanced ionic equation, the number and type of atoms are the same on both sides of the reaction arrow.
Additionally, the net charge is the same on both sides of the equation.
Separate into the complete ionic equation.
It should be obvious that the aquous solutions ionize and the solid is shows as the molecule since it doesn't dissolve.
Cr³⁺(aq) + 3Br⁻(aq) + 3K⁺(aq) + PO₄³⁻(aq) ==> CrPO₄(s) + 3K⁺(aq) + 3Br⁻(aq)
Now look and cancel those ions common to both sides. What is left is the net ionic equation.
Cr³⁺(aq) + PO₄³⁻aq) ==> CrPO₄(s)
Learn more about balanced Ionic equation here ;
brainly.com/question/16463650
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