Answer:
(a)
(b)
Explanation:
Hello,
In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:
Thus, since the final pressure is 3.60 bar, we can write:
The moles of helium could be computed via solver as:
Or algebraically:
In such a way, the volume of the compartment B is:
Finally, he mole fraction of He is:
Regards.
Answer:
The molarity of this solution is 0,09254M
Explanation:
The concentration of the Ni²⁺ solution is:
Ni²⁺ + EDTA⁴⁻ → Ni(EDTA)²⁻
0,03935L × 0,01307M = 5,143x10⁻⁴ moles Ni²⁺ ÷ 0,03010L =<em>0,01709M Ni²⁺</em>
25,00 mL of this solution contain:
0,01709M × 0,02500L = 4,2716x10⁻⁴ moles of Ni²⁺
The moles of Ni²⁺ that are in excess and react with EDTA⁴⁻ are:
0,01015L × 0,01307M = 1,3266x10⁻⁴ moles of Ni²⁺
Thus, moles of Ni²⁺ that react with CN⁻ are:
4,2716x10⁻⁴ - 1,3266x10⁻⁴ = 2,9450x10⁻⁴ moles of Ni²⁺
For the reaction:
4CN⁻ + Ni²⁺ → Ni(CN)₄²⁻
Four moles of CN⁻ react with 1 mole of Ni²⁺:
2,9450x10⁻⁴ moles of Ni²⁺ × = <em>1,178x10⁻³ moles of CN⁻</em>
As the volume of cyanide solution is 12,73mL. The molarity of this solution is:
<em>1,178x10⁻³ moles of CN⁻ ÷ 0,01273L = </em><em>0,09254M</em>
I hope it helps!
Answer:- 1.24 g
Solution:- The balanced equation for the formation of carbonic acid by the reaction of carbon dioxide with water is:
From balanced equation, there is 1:1 mol ratio between carbon dioxide and carbonic acid. So, moles of carbonic acid will be equal to the moles of carbon dioxide used.
Moles of carbon dioxide can be calculated using ideal gas law equation as it's volume, temperature and pressure are given.
we need to convert mL to L, degree C to kelvin and kilopascals to atm.
= 0.495 L
25 + 273 = 298 K
= 1 atm
Ideal gas law equation is:
PV = nRT
We want to find out the n, so let's rearrange this:
R is the universal gas constant and it's value is .
Let's pug in the values in the equation and solve it for n.
n = 0.02 mol
To convert the moles to grams we multiply the moles by the molar mass of carbonic acid.
Molar mass of carbonic acid = 2(1.008)+12.01+3(16.00)
= 2.016+12.01+48.00
= 62.03 gram per mol (rounded to two decimal places)
Let's multiply the moles by molar mass:
= 1.24 g
So, the theoretical yield of carbonic acid is 1.24 g.