What is the volume of the figure below, which is composed of two cubes with side lengths of 9 units

What is the quotient of 2 1/5 ÷ 6 3/5 A. 1/3 B. 3/4 C. 24/35 D. 2/3

zepelin [54]

Answer:

A.1/3

Step-by-step explanation:

on the picture

if it's helpful ❤❤❤

THANK YOU.

7 0

2 years ago

Triangle ABC with A at 0 comma 0, B at 2 comma 4 and C at 0 comma 2, the measure of angle C is 127 degrees, and the measure of a

Nikolay [14]

Answer:

The Answer is B.

Step-by-step explanation:

I got it right on my test

For further evidence here is a picture of the answer

6 0

2 years ago

Twelve people are given two identical speakers, which they are asked to listen to for differences, if any. Suppose that these pe

ruslelena [56]

Answer:

0.0537

Step-by-step explanation:

This follows a binomial distribution with : n

Number of trials 'N' = 12 ; Probability of success (difference between speakers) 'p' = 1/2 or 0.5 ; Probability of failure (no difference b/w speakers) = 1/2 or 0.5 ; No of success 'r' = 3

P (X = 3) = $N C r. (p)^r.(q)^(n-r)\\$

= 12C3 (0.5)^3 (0.5)^9

0.0537

7 0

3 years ago

Which of the following is the correct factorization of the polynomial below? x3 + 14x2 + 49x

Naddika [18.5K]

For this case we must factor the following polynomial:

$x ^ 3 + 14x ^ 2 + 49x\\$

We can take common factor x:

$x(x ^ 2+ 14x + 49)$

To factor the expression within the parenthesis, we must find two numbers that when multiplied give 49 and when added together, 14 are obtained. These are: 7 and 7.

$7*7=49,7+7=14$

Thus, the expression is factored as:

$x(x + 7)(x +7)$

Answer:

$x (x + 7) ^ 2$

7 0

3 years ago

Read 2 more answers

what is the answer here 90 student went to the zoo, 3 had hamburger milk and cake; had 5 milk and hamburger; 10 had cake and mil

dangina [55]

Answer:

a) 37

b) 2

c) 17

d) 8

Step-by-step explanation:

90 Students went to the zoo. 3 had hamburger, milk and cake; 5 had milk and hamburger, 10 had cake and milk; 8 had cake and hamburger; 24 had hamburger; 38 had cake; 20 had milk. How many had a. nothing b. cake only c. milk only d. hamburger only

Solution:

Let h represent students that ate hamburger, m represent students that had milk and c represent students that had cake.

Given that:

n(h ∩ m ∩ c) = 3, n(m ∩ h) = 5, n(c ∩ m) = 10, n(c ∩ h) = 8, n(h) = 24, n(c) = 38, n(m) = 20

The number of students that had nothing = n(h ∪ m ∪ C)'

The number of students that had only milk = n(m ∩ h' ∩ C')

The number of students that had only cake = n(m' ∩ h' ∩ C)

The number of students that had only hamburger = n(m' ∩ h ∩ C')

a) n(m ∩ h' ∩ C') = n(m) - n(m ∩ h) - n(c ∩ m) - n(h ∩ m ∩ c) = 20 - 5 - 10 - 3 = 2

n(m' ∩ h ∩ C') = n(h) - n(m ∩ h) - n(c ∩ h) - n(h ∩ m ∩ c) = 24 - 5 - 8 - 3 = 8

n(m' ∩ h' ∩ C) = n(m) - n(m ∩ c) - n(c ∩ h) - n(h ∩ m ∩ c) = 38 - 10 - 8 - 3 = 17

n(m ∩ h' ∩ C') + n(m' ∩ h ∩ C') + n(m' ∩ h' ∩ C) + n(h ∪ m ∪ C)' + n(h ∩ m ∩ c) + n(m ∩ h) + n(c ∩ m) + n(c ∩ h) = 90

2 + 8 + 17 + 5 + 10 + 8 + 3 + n(h ∪ m ∪ C)' = 90

53 + n(h ∪ m ∪ C)' = 90

n(h ∪ m ∪ C)' = 37

b) n(m' ∩ h' ∩ C) = 17

c) n(m ∩ h' ∩ C') = 2

d) n(m' ∩ h ∩ C') = 8

4 0

2 years ago