The sum of 5 consecutive integers is 505. what is the third number in this sequence
2 answers:
The answer is 101. The number 505 can be divided into 5 different sums and 101 is the third number.
The five numbers are 99,100,101,102,103. Therefore 101 is the third number.
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-2........................
(6x–1)(6x+1) - 4x(9x+2) = −1
Simplify the left side:
36x^2-1 -36x^2-8x = -1
Combine like terms:
-1 -8x = -1
Add 1 to both sides:
-8x = 0
Divide both sides by -8:
x = 0 / -8
x = 0
The root is 0