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Semenov [28]
3 years ago
10

Write your question here. We can't read your mind. Yet.

Mathematics
1 answer:
Brut [27]3 years ago
8 0
What’s the question????????
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Three sets Venn diagram
Anon25 [30]

Answer:

I hope this helps a little bit

8 0
3 years ago
A newspaper wants to estimate the proportion of Americans who will vote for Candidate A. A random sample of 1000 voters is selec
masya89 [10]

Answer:

the excel that would be used to construct a confident interval estimate is (A) NORM.S.INV

Step-by-step explanation:

NORM>S>INV returns the of the standard normal cumulative distribution.

4 0
4 years ago
All of the following ratios are equivalent except<br> 4<br> 8 to 12<br> 2:3<br> 09
Gemiola [76]

Answer:

The answer is 2:3 as the order is different. Simplified the first option is 2:3, the second one: 2:3, the third one 3:2 and the fourth one 2:3

7 0
3 years ago
Kay is a student in Mrs. Hudson’s class. Assuming you know nothing else about Kay, what is the probability that Kay’s birthday w
Drupady [299]

Answer:

262/365

Step-by-step explanation:

So as you can see there is no more information aout Kay on her birthday, so the chances of her birthday being on a week day is given by the total number of the weekdays of the year between the total number of days in a year, so in 2019 there are 262 weekdays, divided by 365 you get the probability that Kay´s birthday falls on a weekday.

262/365=,7178=71,78%

So the probability of Kay´s brithday falling on a week day will be 71,72%

5 0
3 years ago
A marketing firm is asked to estimate the percent of existing customers who would purchase a "digital upgrade" to their basic ca
Ugo [173]

Answer: A. 664

Step-by-step explanation:

Given : A marketing firm is asked to estimate the percent of existing customers who would purchase a "digital upgrade" to their basic cable TV service.

But there is no information regarding the population proportion is mentioned.

Formula to find the samples size , if the prior estimate to the population proportion is unknown :

n=0.25(\dfrac{z*}{E})^2

, where E = Margin of error.

z* = Two -tailed critical z-value

We know that critical value for 99% confidence interval = z*=2.576  [By z-table]

Margin of error = 0.05

Then, the minimum sample size would become :

n=0.25(\dfrac{2.576}{0.05})^2

Simplify,

n=0.25\times2654.3104=663.5776\approx664

Thus, the required sample size= 664

Hence, the correct answer is A. 664.

5 0
4 years ago
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