Answer:
1) Inequality: 110x>150+85x
2) Solution: x>6, then Nadia would need to sell more than 6 ads per week in order for Choice A to be the better choice,
<u>Solution:</u>
Be x the number of ads Nadia sells
A) Choice A: $110 for each ad she sells. She would earn:
Ea=110x
B) Choice B: A weekly salary of $150, plus $85 for each ad she sells. She would earn:
Eb=150+85x
1) Write an inequality to determine the number of ads Nadia would need to seel per week in order for Choice A to be the better choice:
Ea>Eb
110x>150+85x
2) Solution
Solving for x: Subtracting 85x both sides of the equation:
110x-85x>150+85x-85x
Subtracting:
25x>150
Dividing both sides of the equation by 25:
25x/25>150/25
Dividing:
x>6
Ax+ab=c; 2x2 = 9
Try to take it from there
I'd suggest re-wording your question:
"How do I find the ordered pair (x,y) that solves this system of linear equations?"
One way of doing that would be to substitute y=5x+7 into the other equation:
-3x - 2(5x+7) = -12. Solve this for x. Once you have a value for x, subst. that value into y=5x+7 to find the corresponding y value.
Then write the ordered pair (x,y). That's it.
(a) I'd say sometimes true. 3 + -7= -4 , -5 + 3= -2 , 8+-5=3, 7+-7=0
(b) I'm not too sure about this one but I what i know is that if the positive number is higher than the negative number it will be a positive. If you are adding both a negative number and a positive number that is the same value it will be 0. And if you are adding a negative that is higher than the positive it will be a negative number.
I hope this helped a bit.. (:
