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Rom4ik [11]
3 years ago
11

F(x)=7e^-2t growth or decay

Mathematics
1 answer:
Roman55 [17]3 years ago
7 0
\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\\ \quad \\\\ %  negative exponential denominator
a^{{ n}} \implies \cfrac{1}{a^{- n}}
\qquad \qquad 
\cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}} \\\\
-----------------------------\\\\
f(x)=7e^{-2t}\iff f(x)=7\cdot \cfrac{1}{e^{2t}}\iff f(x)=\cfrac{7}{e^{2t}}


as "t" grows larger and larger, 10, 100, 10000, 1000000 and so on, the denominator becomes larger and larger, whilst the numerator is static, thus, the fraction becomes smaller and smaller

as "t" increases, f(x) decreases, decay
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