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3 years ago

The graph y=ln(x) is translated 7 units to the left and 4 units upward. The transformed equation is ____.

1 answer:

5 0

When x is replaced by x - h, the graph shifts h units to the right if h is positive and h units to the left if h is negative.
When y is replaced by y - k, the graph shifts k units up if k is positive, and k units down is k is negative.

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Simplify the surd 3√ 20 +√ 45

melisa1 [442]

Answer:

9 $\sqrt{5}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplify the radicals

$\sqrt{20}$

= $\sqrt{4(5)}$

= $\sqrt{4}$ × $\sqrt{5}$

= 2 $\sqrt{5}$

$\sqrt{45}$

= $\sqrt{9(5)}$

= $\sqrt{9}$ × $\sqrt{5}$

= 3 $\sqrt{5}$

Then

3 $\sqrt{20}$ + $\sqrt{45}$

= 3(2 $\sqrt{5}$ ) + 3 $\sqrt{5}$

= 6 $\sqrt{5}$ + 3 $\sqrt{5}$

= 9 $\sqrt{5}$

3 0

3 years ago

Read 2 more answers

Growth Models 19515. In 1968, the U.S. minimum wage was $1.60 per hour. In 1976, the minimum wagewas $2.30 per hour. Assume the

VikaD [51]

In general, the exponential growth function is given by the formula below

$f(x)=a(1+r)^x$

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

$\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}$

And 1976 is n=16

$\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}$

Solve the two equations simultaneously, as shown below

$\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}$

Solving for a,