It has been proven that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
<h3>How to prove a Line Segment?</h3>
We know that in a triangle if one angle is 90 degrees, then the other angles have to be acute.
Let us take a line l and from point P as shown in the attached file, that is, not on line l, draw two line segments PN and PM. Let PN be perpendicular to line l and PM is drawn at some other angle.
In ΔPNM, ∠N = 90°
∠P + ∠N + ∠M = 180° (Angle sum property of a triangle)
∠P + ∠M = 90°
Clearly, ∠M is an acute angle.
Thus; ∠M < ∠N
PN < PM (The side opposite to the smaller angle is smaller)
Similarly, by drawing different line segments from P to l, it can be proved that PN is smaller in comparison to all of them. Therefore, it can be observed that of all line segments drawn from a given point not on it, the perpendicular line segment is the shortest.
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The answer is A Ezra is right
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Step-by-step explanation:I have made this reasoning: an eyelet consists of two semicircles and a rectangle (or two semirectangle), then a semicircle and a semirectangle ..But some irregular figures are made up of two or more standard geometric shapes. To find the ... We will break the figure into a rectangle and two semi-circles.
Answer:
a
Step-by-step explanation:
Answer:
-7
Step-by-step explanation:
y-intercept
x=0
y-3= -2x-10
y=2(0)-10+3
y=0-7
y= -7
(0;-7)