What is the domain of y=3^x-2 +1

the space suit Neil Armstrong when he stepped on the ball for the first time with about 8 and 180 pounds on Earth how much do th

BigorU [14]

The weight would be converted to 30 pounds on the moon

8 0

3 years ago

The scatter plot shows the number of flowers that have bloomed in the garden during the month of March:

Elodia [21]

Answer:

A: A coefficient of 0.98 shows a strong positive correlation with the data.

B: A graph comparing the number of seeds planted to the number of flowers in a garden.

Explanation:

A: Because, a correlation coefficient of 1 means there is a direct positive correlation correlation anyting over 0.5 shows a strong posotive correlation.

B: Any relationship where the first value directly causes the second is a causual relationship.

6 0

3 years ago

Jenny purchased a prepaid phone card for $30.Long distance calls cost 12 cents a minute using this card. Jenny used her card onl

Korolek [52]

Answer:

43 min

Step-by-step explanation:

subtract $24.84 from $30 and you get $5.16 and you divide that by 12 cents which then you get 43 min

4 0

3 years ago

In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of

In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

A line segment joining the mid-points of two sides in a triangle is parallel to the third side and equal to half its length

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = $\frac{1}{2}$ MN

∵ JL = 11 units

∴ 11 = $\frac{1}{2}$ MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = $\frac{1}{2}$ MO

∵ KL = 13 units

∴ 13 = $\frac{1}{2}$ MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = $\frac{1}{2}$ ON

∵ ON =20 units

∴ JK = $\frac{1}{2}$ (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=2%28%203x%20%2B%201%29%20%3D%2011" id="TexFormula1" title="2( 3x + 1) = 11" alt="2( 3x + 1) =

lisabon 2012 [21]

I'm assuming you need to evaluate/simplify the equation, so you need to isolate/get x by itself in the equation:

2(3x + 1) = 11 Divide by 2 on both sides

3x + 1 = $\frac{11}{2}$ [11/2 or 5.5] Subtract by 1 on both sides

$3x=\frac{11}{2}-\frac{2}{2}$ [make the denominator the same to combine fractions]

3x = $\frac{9}{2}$ Divide by 3 on both sides

x = $\frac{9}{6}=\frac{3}{2}$

7 0

3 years ago