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Tju [1.3M]
2 years ago
5

Factor out -2 out of -6x+10

Mathematics
3 answers:
Schach [20]2 years ago
7 0

lagged out and posted twice my bad

if anybody knows how to delete this, comment below please

topjm [15]2 years ago
5 0
-2 (3x -5)
..............
hram777 [196]2 years ago
5 0

If you want to factor -2 out of -6x + 10, simply divide everything by -2 and put the result in a parentheses times -2:

(-6x + 10)/-2 = 3x - 5

Therefore, the factored form would be -2(3x - 5).

If you want to check the answer, just redistribute the -2:

-2 * 3x = -6x and -2 * -5 = 10

-6x + 10 <----- It checks out

<em>Hope this helps! :)</em>

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Can 9, 6, and 5 be the lengths of the sides of a triangle? (yes or no answer)
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Solve for x<br><img src="https://tex.z-dn.net/?f=0%20%3D%20%20-%20%7B%20e%20%7D%5E%7B%20-%20x%7D%20%20%2B%203%20%7Be%7D%5E%7B3x%
Brilliant_brown [7]

\bf \textit{Logarithm Cancellation Rules} \\\\ \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{log_a a^x = x}\qquad \qquad a^{log_a x}=x~\hfill\stackrel{recall}{ln=log_e}\qquad log_e(e^z)=z \\\\[-0.35em] \rule{34em}{0.25pt}


\bf 0=-e^{-x}+3e^{3x}\implies e^{-x}=3e^{3x}\implies \cfrac{1}{e^x}=3e^{3x}\implies 1=e^x\cdot 3e^{3x} \\\\\\ 1=3e^xe^{3x}\implies \cfrac{1}{3}=e^{x+3x}\implies \cfrac{1}{3}=e^{4x}\implies ln\left( \cfrac{1}{3} \right)=ln\left( e^{4x} \right) \\\\\\ ln\left( \cfrac{1}{3} \right)=4x\implies \cfrac{ln\left( \frac{1}{3} \right)}{4}=x


and you plug that in your calculator to get about -0.27465307216702742285.

8 0
3 years ago
Can someone please help PLEASE ​
Lena [83]
U: -2,-2
B: -5, 0
K: -5, -3
Y: -4, -3

I believe so..
7 0
2 years ago
In this rectangular box, EF = 16, FD = 5, and DB = 30. Find AF.
AVprozaik [17]

Answer:

FA = 25.87  

Step-by-step explanation:

Given: BD = 30 , DF = 5 , EF = 16

To find: FA

Rectangular box is a Cuboid.

Figure attached.

AB = FE = 16

So,

In  ΔADB

using Pythagoras theorem,

DB^2=AB^2+AD^2\\30^2=16^2+AD^2\\900=256+AD^2\\AD^2=900-256\\AD^2=644\\AD=\sqrt{644}\\AD=2\sqrt{161}

Again using Pythagoras theorem in Δ ADF we get

FA^2=DF^2+AD^2\\FA^2=5^2+(2\sqrt{161})^2\\FA^2=25+644\\FA^2=669\\FA=\sqrt{669}\\FA=25.87

Therefore, FA = 25.87

6 0
3 years ago
Read 2 more answers
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