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Airida [17]
3 years ago
6

What is x=5y-1 x+2y=13

Mathematics
2 answers:
Anon25 [30]3 years ago
5 0
<span>x=5y-1
x+2y=13 => 5y -1 +2y = 13 => 7y = 14 => y = 2 => x = 9;</span>
djverab [1.8K]3 years ago
5 0

Answer: x = 9, y = 2

Step-by-step explanation:

plug in values and solve.

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anygoal [31]

Answer:

C. Various fees paid when a home purchase is finalized

6 0
3 years ago
Which function has a phase shift of pi/2 to the right?
Bess [88]
If it helps you any

\bf \qquad \qquad \qquad \qquad \textit{function transformations}&#10;\\ \quad \\&#10;% function transformations for trigonometric functions&#10;\begin{array}{rllll}&#10;% left side templates&#10;f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;&#10;\end{array}

\bf \begin{array}{llll}&#10;% right side info&#10;\bullet \textit{ stretches or shrinks}\\&#10;\quad \textit{horizontally by amplitude } |{{  A}}|\\&#10;\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\&#10;\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\&#10;\end{array}

\bf \begin{array}{llll}&#10;&#10;\bullet \textit{vertical shift by }{{  D}}\\&#10;\qquad if\ {{  D}}\textit{ is negative, downwards}\\&#10;\qquad if\ {{  D}}\textit{ is positive, upwards}\\&#10;\bullet \textit{function period}\\&#10;\qquad \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\&#10;\qquad \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)&#10;\end{array}

so.. check coefficients C and B for the horizontal shift
7 0
3 years ago
Read 2 more answers
536-248 answer and show your work
Anni [7]

Answer:

288

Step-by-step explanation:

288+248=536

8 0
2 years ago
Which of the following points is on a circle if its center is (-13,-12) and a point on the circumference is (-17, -12)?
tia_tia [17]

Answer:

D

Step-by-step explanation:

Obtain the equation of the circle in standard form

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

here (h, k) = (- 13, - 12), thus

(x + 13)² + (y + 12)² = r²

The radius is the distance from the centre (- 13, - 12) to the point on the circumference (- 17, - 12)

Use the distance formula to calculate r

r = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 17, - 12) and (x₂, y₂ ) = (- 13, -12)

r = \sqrt{(-13+17)^2+(-12+12)^2} = \sqrt{16} = 4

Hence

(x + 13)² + (y + 12)² = 16 ← in standard form

Substitute the coordinates of each point into the left side of the equation and check

A (- 17, - 13) : (- 4)² + (- 1)² = 16 + 1 = 17 ≠ 16

B (- 9, - 17) : 4² + (- 5)² = 16 + 25 = 41 ≠ 16

C (- 12, 13) : 1² + 25² ≠ 16

D (- 9, - 12) : 4² + 0² = 16

Since (- 9, - 12) satisfies the equation, it is on the circle → D

4 0
3 years ago
What is the length of line segment AB?
-Dominant- [34]
Your answer to this question is B) 8 Units. For you to be able to do it in the future (for like tests) count from after a point to the end point. In this one start from -4 to point B and you will get 8 units.
7 0
3 years ago
Read 2 more answers
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