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qwelly [4]
3 years ago
12

Write a program that reads an integer, a list of words, and a character. The integer signifies how many words are in the list. T

he output of the program is every word in the list that contains the character at least once. Assume at least one word in the list will contain the given character. Assume that the list will always contain less than 20 words. Each word will always contain less than 10 characters and no spaces Ex: If the input is: 4 hello zoo sleep drizzle z then the output is: zoo drizzle To achieve the above, first read the list into an array. Keep in mind that the character 'a' is not equal to the character 'A' Hint: To read in the character after the final word, add a space before %c: scanf(" %c", &searchCharacter);
Computers and Technology
1 answer:
kompoz [17]3 years ago
3 0

Answer:

I can't read that pls reformat, or take picture.

Explanation:

You might be interested in
Computer operates nearly 100% accurately but why is the phrase'garbage in garbage out'(GIGO) associated with their use?Describe
k0ka [10]

Answer:

A program gives inaccurate results due to inaccurate data provided because a computer will always attempt to process data given to it. Said another way, the output quality of a system usually can't be any better than than the quality of inputs.

Explanation:

Techopedia Explains Garbage In, Garbage Out (GIGO)

<h3>Mark me a brainlist</h3>
8 0
3 years ago
How are most gamepads installed on devices?
Doss [256]

Answer:

Plug and Play

Explanation:

most modern game pads are you just need to plug into a port and then you are free to use without any setting up.

3 0
3 years ago
Note: You can use a word document to write your answers and copy-paste your answer to the area specified. a. (5 points) Convert
MrMuchimi

Answer:

EA9_{16} = 3753

CB2_{16} = 3250

(1011 1110 1101 1011 1010)_2 = 781754

(1010 1000 1011 1000 1110 1101)_2 = 11057389

(1011 1110 1101 1011 1010)_2 = BEDBA

(1010 1000 1011 1000 1110 1101)_2 =  A8B8ED

74510_8= 221416

67210_8 = 203212

Explanation:

Solving (a): To base 10

(i)\ EA9_{16

We simply multiply each digit by a base of 16 to the power of their position.

i.e.

EA9_{16} = E * 16^2 + A * 16^1 + 9 * 16^0

EA9_{16} = E * 256 + A * 16 + 9 * 1

In hexadecimal

A = 10; E = 14

So:

EA9_{16} = 14 * 256 + 10 * 16 + 9 * 1

EA9_{16} = 3753

(ii)\ CB2_{16}

This gives:

CB2_{16} = C * 16^2 + B * 16^1 + 2 * 16^0

CB2_{16} = C * 256 + B * 16 + 2 * 1

In hexadecimal

C = 12; B =11

So:

CB2_{16} = 12 * 256 + 11 * 16 + 2 * 1

CB2_{16} = 3250

Solving (b): To base 10

(i)\ (1011 1110 1101 1011 1010)_2

We simply multiply each digit by a base of 2 to the power of their position.

i.e.

(1011 1110 1101 1011 1010)_2 = 1 * 2^{19} + 0 * 2^{18} + 1 * 2^{17} + 1 * 2^{16} +1 * 2^{15} + 1 * 2^{14} + 1 * 2^{13} + 0 * 2^{12} + 1 * 2^{11} + 1 * 2^{10} + 0 * 2^9 + 1 * 2^8 +1 * 2^7 + 0 * 2^6 + 1 * 2^5 + 1 * 2^4 + 1 * 2^3 + 0 * 2^2 + 1 * 2^1 + 0 * 2^0

(1011 1110 1101 1011 1010)_2 = 781754

(ii)\ (1010 1000 1011 1000 1110 1101)_2

(1010 1000 1011 1000 1110 1101)_2 = 1 * 2^{23} + 0 * 2^{22} + 1 * 2^{21} + 0 * 2^{20} +1 * 2^{19} + 0 * 2^{18} + 0 * 2^{17} + 0 * 2^{16} + 1 * 2^{15} + 0 * 2^{14} + 1 * 2^{13} + 1 * 2^{12} +1 * 2^{11} + 0 * 2^{10} + 0 * 2^9 + 0 * 2^8 + 1 * 2^7 + 1 * 2^6 + 1 * 2^5 + 0 * 2^4 + 1*2^3 + 1 * 2^2 + 0 * 2^1 + 1 * 2^0

(1010 1000 1011 1000 1110 1101)_2 = 11057389

Solving (c): To base 16

i.\ (1011 1110 1101 1011 1010)_2

First, convert to base 10

In (b)

(1011 1110 1101 1011 1010)_2 = 781754

Next, is to divide 781754 by 16 and keep track of the remainder

781754/16\ |\ 48859\ R\ 10

48859/16\ |\ 3053\ R\ 11

3053/16\ |\ 190\ R\ 13

190/16\ |\ 11\ R\ 14

11/16\ |\ 0\ R\ 11

Write out the remainder from bottom to top

(11)(14)(13)(11)(10)

In hexadecimal

A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.

(11)(14)(13)(11)(10)=BEDBA

So:

(1011 1110 1101 1011 1010)_2 = BEDBA

ii.\ (1010 1000 1011 1000 1110 1101)_2

In b

(1010 1000 1011 1000 1110 1101)_2 = 11057389

Next, is to divide 11057389 by 16 and keep track of the remainder

11057389/16\ |\ 691086\ R\ 13

691086/16\ |\ 43192\ R\ 14

43192/16\ |\ 2699\ R\ 8

2699/16\ |\ 168\ R\ 11

168/16\ |\ 10\ R\ 8

10/16\ |\ 0\ R\ 10

Write out the remainder from bottom to top

(10)8(11)8(14)(13)

In hexadecimal

A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.

(10)8(11)8(14)(13) = A8B8ED

So:

(1010 1000 1011 1000 1110 1101)_2 =  A8B8ED

Solving (d): To octal

(i.)\ 74510

Divide 74510 by 8 and keep track of the remainder

74510/8\ |\ 9313\ R\ 6

9313/8\ |\ 1164\ R\ 1

1164/8\ |\ 145\ R\ 4

145/8\ |\ 18\ R\ 1

18/8\ |\ 2\ R\ 2

2/8\ |\ 0\ R\ 2

Write out the remainder from bottom to top

74510_8= 221416

(ii.)\ 67210

Divide 67210 by 8 and keep track of the remainder

67210/8\ |\ 8401\ R\ 2

8401/8\ |\ 1050\ R\ 1

1050/8\ |\ 131\ R\ 2

131/8\ |\ 16\ R\ 3

16/8\ |\ 2\ R\ 0

2/8\ |\ 0\ R\ 2

Write out the remainder from bottom to top

67210_8 = 203212

8 0
4 years ago
Two time series techniques that are appropriate when the data display a strong upward or downward trend are ___________ and ____
VMariaS [17]

Answer:

adjusted exponential smoothing; linear regression.

Explanation:

A time series can be defined as a technique used in statistical analysis and it involves indexing sets of data elements in a timely or successive order i.e sequentially.

Two time series techniques that are appropriate when the data display a strong upward or downward trend are adjusted exponential smoothing and linear regression.

An adjusted exponential smoothing is a statistical technique used for forecasting through the calculation of the weighted average of an actual value.

5 0
3 years ago
6. The NADH and FADH2 produced during the Krebs cycle pass their electrons down the 7. __ __ __ __ __ __ __ __ __ __ __ __ __ __
AlladinOne [14]

Answer:

The NADH and FADH2 produced during the Krebs cycle pass the electrons down  electron transport chain in the mitochondria to generate more ATP molecules

Explanation:

FADH2 stands for Flavin adenine dinucleotide and NADH stands for Nicotinamide adenine dinucleotide.

Both are created from FAD and NAD+ through reduction-oxidation reactions in the Krebs cycle during respiration as explained below:

This cycle gives off small amounts of energy in the form of adenosine triphosphate, or ATP, and produces these compounds, FADH2 and NADH. The Krebs cycle is like a wheel. Every time it makes one full rotation, energy is created and released. As you can see from the diagram, the NAD+ and FAD are brought in at key points throughout the cycle and are attached to other electrons resulting in the formation of NADH and FADH2.

This energy is then shuttled off to be used by the cell, mostly for the continuation of cellular respiration.

As they are shuttled away, these two compounds are used to move electrons into the electron transport chain, the final stage of respiration. It is in this stage that most of the energy is created and released from the mitochondria (powerhouse of the cell).

Basically the NADH and FADH2 are affixed with electrons and tranfered to the inner membrane of the mitochondria. The travel down the electron transfer chain, releasing electrons they once had. Thereby releasing alot of energy in the process

3 0
4 years ago
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