Answer:
90
Explanation:
dur nearly all my friends and family knows that
Answer:
Number of packets ≈ 5339
Explanation:
let
X = no of packets that is not erased.
P ( each packet getting erased ) = 0.8
P ( each packet not getting erased ) = 0.2
P ( X ≥ 1000 ) = 0.99
E(x) = n * 0.2
var ( x ) = n * 0.2 * 0.8
∴ Z = X - ( n * 0.2 ) / 
~ N ( 0.1 )
attached below is the remaining part of the solution
note : For the value of <em>n</em> take the positive number
Answer:
for ( initialization; condition;increment)
{
code goes here;
}
in python:
for i in list/range:
code with proper indentation
By initialization above we mean, like int i=0; etc.
By condition like i<10;
and by increment it means like i++, ++i or i+=1; etc
And in python, i can be an integer value if the range is mentioned, and it can be an item of a list if the list is used. We can also use an array, string and various other data structures in python. like we can have characters in a string and so on.
Explanation:
Please check the answer section.
Thank you for being the rare question where you actually provide what language you want your answer in; I approve, and encourage this.
In Java, the following will work.
I made it a bit more versatile to work with others numbers, other than 99, if you so please (if not, just hardcode the 99 in yourself).
// Example list - fill this with numbers yourself.
ArrayList<Integer> nums = new ArrayList<>();
int n = 99;
int count = (int)nums.stream().filter(i -> i == n).count();
System.out.println(n + " occurences.");
